Quoting Maulik Shah (2020-05-27 04:26:14)i don't think this will be a problem.
On 5/27/2020 3:14 PM, Stephen Boyd wrote:Sure a consumer can disable the lazy feature, but that shouldn't be
Quoting Maulik Shah (2020-05-23 10:11:10)The client driver can decide to unlazy disable IRQ with below API...
diff --git a/drivers/gpio/gpiolib.c b/drivers/gpio/gpiolib.cHow does this work in the lazy case when I want to drive the GPIO? Say I
index eaa0e20..3810cd0 100644
--- a/drivers/gpio/gpiolib.c
+++ b/drivers/gpio/gpiolib.c
@@ -2465,32 +2465,37 @@ static void gpiochip_irq_relres(struct irq_data *d)
gpiochip_relres_irq(gc, d->hwirq);
}
+static void gpiochip_irq_mask(struct irq_data *d)
+{
+ struct gpio_chip *gc = irq_data_get_irq_chip_data(d);
+
+ if (gc->irq.irq_mask)
+ gc->irq.irq_mask(d);
+ gpiochip_disable_irq(gc, d->hwirq);
have a GPIO that is also an interrupt. The code would look like
struct gpio_desc *gpio = gpiod_get(...)
unsigned int girq = gpiod_to_irq(gpio)
request_irq(girq, ...);
disable_irq(girq);
gpiod_direction_output(gpio, 1);
In the lazy case genirq wouldn't call the mask function until the first
interrupt arrived on the GPIO line. If that never happened then wouldn't
we be blocked in gpiod_direction_output() when the test_bit() sees
FLAG_USED_AS_IRQ? Or do we need irqs to be released before driving
gpios?
Âirq_set_status_flags(girq, IRQ_DISABLE_UNLAZY);
This will immediatly invoke mask function (unlazy disable) from genirq,
even though irq_disable is not implemented.
required to make this work. The flag was introduced in commit
e9849777d0e2 ("genirq: Add flag to force mask in
disable_irq[_nosync]()") specifically to help devices that can't disable
the interrupt in their own device avoid a double interrupt.