Re: [PATCH v2 5/8] x86/debug: Simplify #DB signal code
From: Andrew Cooper
Date: Mon Aug 24 2020 - 07:26:47 EST
On 24/08/2020 12:05, peterz@xxxxxxxxxxxxx wrote:
> On Sun, Aug 23, 2020 at 04:09:42PM -0700, Andy Lutomirski wrote:
>> On Fri, Aug 21, 2020 at 3:21 AM Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
>>> Get rid of the two variables, avoid computing si_code when not needed
>>> and be consistent about which dr6 value is used.
>>>
>>> - if (tsk->thread.debugreg6 & (DR_STEP | DR_TRAP_BITS) || user_icebp)
>>> - send_sigtrap(regs, 0, si_code);
>>> + /*
>>> + * If dr6 has no reason to give us about the origin of this trap,
>>> + * then it's very likely the result of an icebp/int01 trap.
>>> + * User wants a sigtrap for that.
>>> + */
>>> + if (dr6 & (DR_STEP | DR_TRAP_BITS) || !dr6)
>>> + send_sigtrap(regs, 0, get_si_code(dr6));
>> The old condition was ... || (actual DR6 value) and the new condition
>> was ... || (stupid notifier-modified DR6 value). I think the old code
>> was more correct.
> Hurmph.. /me goes re-read the SDM.
>
> INT1 is a trap,
> instruction breakpoint is a fault
>
> So if you have:
>
> INT1
> 1: some-instr
>
> and set an X breakpoint on 1, we'll loose the INT1, right?
You should get two. First with a dr6 of 0 (ICEBP, RIP pointing at 1:),
and a second with dr6 indicating the X breakpoint (again, RIP pointing
at 1:).
SDM Vol3 6.9 PRIORITY AMONG SIMULTANEOUS EXCEPTIONS AND INTERRUPTS
Traps on previous instructions are at priority 4, because they still
"part" of the previous instruction. X breakpoints are priority 7.
The two #DB's shouldn't merge because nothing inhibits delivery[1] of
the trap at priority 4, and on return from the handler, RF isn't set so
the instruction breakpoint will trigger.
~Andrew
[1] Anyone playing with MovSS gets to keep all resulting pieces.