Re: [PATCH] mm: fix potential pte_unmap_unlock pte error

[osalvador]

On 2020-10-15 14:15, Shijie Luo wrote:
> When flags don't have MPOL_MF_MOVE or MPOL_MF_MOVE_ALL bits, code 
> breaks
>  and passing origin pte - 1 to pte_unmap_unlock seems like not a good 
> idea.
>
> Signed-off-by: Shijie Luo <luoshijie1@xxxxxxxxxx>
> Signed-off-by: linmiaohe <linmiaohe@xxxxxxxxxx>
> ---
>  mm/mempolicy.c | 6 +++++-
>  1 file changed, 5 insertions(+), 1 deletion(-)
>
> diff --git a/mm/mempolicy.c b/mm/mempolicy.c
> index 3fde772ef5ef..01f088630d1d 100644
> --- a/mm/mempolicy.c
> +++ b/mm/mempolicy.c
> @@ -571,7 +571,11 @@ static int queue_pages_pte_range(pmd_t *pmd,
> unsigned long addr,
>  		} else
>  			break;
>  	}
> -	pte_unmap_unlock(pte - 1, ptl);
> +
> +	if (addr >= end)
> +		pte = pte - 1;
> +
> +	pte_unmap_unlock(pte, ptl);

But this is still wrong, isn't it?
Unless I am missing something, this is "only" important under 
CONFIG_HIGHPTE.

We have:

pte = pte_offset_map_lock(walk->mm, pmd, addr, &ptl);

which under CONFIG_HIGHPTE does a kmap_atomoc.

Now, we either break the loop in the first pass because of 
!(MPOL_MF_MOVE | MPOL_MF_MOVE_ALL),
or we keep incrementing pte by every pass.
Either way is wrong, because the pointer kunmap_atomic gets will not be 
the same (since we incremented pte).

Or is the loop meant to be running only once, so pte - 1 will bring us 
back to the original pte?