Re: [PATCH bpf v6 1/2] lib/strncpy_from_user.c: Don't overcopy bytes after NUL terminator
From: Ivan Kokshaysky
Date: Tue Nov 17 2020 - 13:41:12 EST
On Mon, Nov 16, 2020 at 02:44:56PM -0800, Linus Torvalds wrote:
> On Mon, Nov 16, 2020 at 2:15 PM Linus Torvalds
> <torvalds@xxxxxxxxxxxxxxxxxxxx> wrote:
> >
> > So I've verified that at least on x86-64, this doesn't really make
> > code generation any worse, and I'm ok with the patch from that
> > standpoint.
>
> .. looking closer, it will generate extra code on big-endian
> architectures and on alpha, because of the added "zero_bytemask()".
> But on the usual LE machines, zero_bytemask() will already be the same
> as "mask", so all it adds is that "and" operation with values it
> already had access to.
>
> I don't think anybody cares about alpha and BE - traditional BE
> architectures have moved to LE anyway. And looking at the alpha
> word-at-a-time code, I don't even understand how it works at all.
>
> Adding matt/rth/ivan to the cc, just so that maybe one of them can
> educate me on how that odd alpha zero_bytemask() could possibly work.
> The "2ul << .." part confuses me, I think it should be "1ul << ...".
>
> I get the feeling that the alpha "2ul" constant might have come from
> the tile version, but in the tile version, the " __builtin_ctzl()"
> counts the leading zeroes to the top bit of any bytes in 'mask'. But
> the alpha version actually uses "find_zero(mask) * 8", so rather than
> have values of 7/15/23/... (for zero byte in byte 0/1/2/..
> respectively), it has values 0/8/16/....
>
> But it's entirely possible that I'm completely confused, and alpha
> does it right, and I'm just not understanding the code.
No, you are right, it should be "1ul". Indeed, seems like it came from
the tile version which looks incorrect either, BTW. The tile-gx ISA
(https://studylib.net/doc/18755547/tile-gx-instruction-set-architecture)
says that clz/ctz instructions count up to the first "1", not to the
last "0", so the shift values in tile's zero_bytemask() are 0/8/16/...
as well.
> It's also possible that the "2ul" vs "1ul" case doesn't matter.
> because the extra bit is always going to mask the byte that is
> actually zero, so being one bit off in the result is a non-event. I
> think that is what may actually be going on.
Yes, looks like that.
Ivan.