Re: [PATCH] spi: spi-geni-qcom: Fix NULL pointer access in geni_spi_isr

[Doug Anderson]

Hi,

On Thu, Dec 10, 2020 at 5:39 PM Stephen Boyd <swboyd@xxxxxxxxxxxx> wrote:
>
> Quoting Doug Anderson (2020-12-10 17:30:17)
> > On Thu, Dec 10, 2020 at 5:21 PM Stephen Boyd <swboyd@xxxxxxxxxxxx> wrote:
> > >
> > > Yeah and so if it comes way later because it timed out then what's the
> > > point of calling synchronize_irq() again? To make the completion
> > > variable set when it won't be tested again until it is reinitialized?
> >
> > Presumably the idea is to try to recover to a somewhat usable state
> > again?  We're not rebooting the machine so, even though this transfer
> > failed, we will undoubtedly do another transfer later.  If that
> > "abort" interrupt comes way later while we're setting up the next
> > transfer we'll really confuse ourselves.
>
> The interrupt handler just sets a completion variable. What does that
> confuse?

The interrupt handler sees a "DONE" interrupt.  If we've made it far
enough into setting up the next transfer that "cur_xfer" has been set
then it might do more, no?


> > I guess you could go the route of adding a synchronize_irq() at the
> > start of the next transfer, but I'd rather add the overhead in the
> > exceptional case (the timeout) than the normal case.  In the normal
> > case we don't need to worry about random IRQs from the past transfer
> > suddenly showing up.
> >
>
> How does adding synchronize_irq() at the end guarantee that the abort is
> cleared out of the hardware though? It seems to assume that the abort is
> pending at the GIC when it could still be running through the hardware
> and not executed yet. It seems like a synchronize_irq() for that is
> wishful thinking that the irq is merely pending even though it timed
> out and possibly never ran. Maybe it's stuck in a write buffer in the
> CPU?

I guess I'm asserting that if a full second passed (because we timed
out) and after that full second no interrupts are pending then the
interrupt will never come.  That seems a reasonable assumption to me.
It seems hard to believe it'd be stuck in a write buffer for a full
second?

-Doug