Re: [PATCH v2 14/48] opp: Filter out OPPs based on availability of a required-OPP

[Viresh Kumar]

On 17-12-20, 21:06, Dmitry Osipenko wrote:
> A required OPP may not be available, and thus, all OPPs which are using
> this required OPP should be unavailable too.
> 
> Signed-off-by: Dmitry Osipenko <digetx@xxxxxxxxx>
> ---
>  drivers/opp/core.c | 11 ++++++++++-
>  1 file changed, 10 insertions(+), 1 deletion(-)

Please send a separate patchset for fixes, as these can also go to 5.11 itself.

> diff --git a/drivers/opp/core.c b/drivers/opp/core.c
> index d9feb7639598..3d02fe33630b 100644
> --- a/drivers/opp/core.c
> +++ b/drivers/opp/core.c
> @@ -1588,7 +1588,7 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
>  	     struct opp_table *opp_table, bool rate_not_available)
>  {
>  	struct list_head *head;
> -	int ret;
> +	int i, ret;
>  
>  	mutex_lock(&opp_table->lock);
>  	head = &opp_table->opp_list;
> @@ -1615,6 +1615,15 @@ int _opp_add(struct device *dev, struct dev_pm_opp *new_opp,
>  			 __func__, new_opp->rate);
>  	}
>  
> +	for (i = 0; i < opp_table->required_opp_count && new_opp->available; i++) {
> +		if (new_opp->required_opps[i]->available)
> +			continue;
> +
> +		new_opp->available = false;
> +		dev_warn(dev, "%s: OPP not supported by required OPP %pOF (%lu)\n",
> +			 __func__, new_opp->required_opps[i]->np, new_opp->rate);

Why not just break from here ?

> +	}
> +
>  	return 0;
>  }
>  
> -- 
> 2.29.2

-- 
viresh