On Fri, Apr 09, 2021 at 09:50:20AM -0400, Liang, Kan wrote:
On 4/9/2021 2:58 AM, Peter Zijlstra wrote:
On Mon, Apr 05, 2021 at 08:10:58AM -0700, kan.liang@xxxxxxxxxxxxxxx wrote:
@@ -2089,9 +2119,46 @@ static int __init init_hw_perf_events(void)
if (err)
goto out1;
- err = perf_pmu_register(&pmu, "cpu", PERF_TYPE_RAW);
- if (err)
- goto out2;
+ if (!is_hybrid()) {
+ err = perf_pmu_register(&pmu, "cpu", PERF_TYPE_RAW);
+ if (err)
+ goto out2;
+ } else {
+ u8 cpu_type = get_this_hybrid_cpu_type();
+ struct x86_hybrid_pmu *hybrid_pmu;
+ bool registered = false;
+ int i;
+
+ if (!cpu_type && x86_pmu.get_hybrid_cpu_type)
+ cpu_type = x86_pmu.get_hybrid_cpu_type();
+
+ for (i = 0; i < x86_pmu.num_hybrid_pmus; i++) {
+ hybrid_pmu = &x86_pmu.hybrid_pmu[i];
+
+ hybrid_pmu->pmu = pmu;
+ hybrid_pmu->pmu.type = -1;
+ hybrid_pmu->pmu.attr_update = x86_pmu.attr_update;
+ hybrid_pmu->pmu.capabilities |= PERF_PMU_CAP_HETEROGENEOUS_CPUS;
+
+ err = perf_pmu_register(&hybrid_pmu->pmu, hybrid_pmu->name,
+ (hybrid_pmu->cpu_type == hybrid_big) ? PERF_TYPE_RAW : -1);
+ if (err)
+ continue;
+
+ if (cpu_type == hybrid_pmu->cpu_type)
+ x86_pmu_update_cpu_context(&hybrid_pmu->pmu, raw_smp_processor_id());
+
+ registered = true;
+ }
+
+ if (!registered) {
+ pr_warn("Failed to register hybrid PMUs\n");
+ kfree(x86_pmu.hybrid_pmu);
+ x86_pmu.hybrid_pmu = NULL;
+ x86_pmu.num_hybrid_pmus = 0;
+ goto out2;
+ }
I don't think this is quite right. registered will be true even if one
fails, while I think you meant to only have it true when all (both)
types registered correctly.
No, I mean that perf error out only when all types fail to be registered.
All or nothing seems a better approach to me. There really isn't a good
reason for any one of them to fail.