Re: [RFC PATCH] timer: Fix bucket_expiry calculation

From: Xiongfeng Wang
Date: Thu May 13 2021 - 02:51:23 EST


Hi Thomas,

On 2021/5/12 22:42, Thomas Gleixner wrote:
> Xiongfeng,
>
> On Wed, May 12 2021 at 20:15, Xiongfeng Wang wrote:
>> When I use schedule_timeout(5) to put a process into sleep on my machine
>> with HZ = 100. It always sleep about 60ms. I enable the timer trace and
>> find out, when the timer_list expires, 'now' is always equal to
>> 'expires + 1'. I print 'base->next_expiry' in '__run_timers' and find out
>> 'next_expiry' is always equal to 'expires + 1';
>>
>> It is because we use the following equation to calculate bucket_expiry.
>>
>> bucket_expiry = ((expires + LVL_GRAN(lvl)) >> LVL_SHIFT(lvl)) << LVL_SHIFT(lvl)
>>
>> 'bucket_expiry' is equal to 'expires + 1' when lvl = 0. So modify the
>> equation as follows to fix the issue.
>>
>> bucket_expiry = ((expires + LVL_GRAN(lvl) - 1) >> LVL_SHIFT(lvl)) << LVL_SHIFT(lvl)
>
> That's wrong because you move the expiry of each timer one jiffie ahead,
> which violates the guarantee that a timer sleeps at least for one jiffie
> for real and not measured in jiffies.
>
> jiffies = 0
> schedule_timeout(1)
>
> local_irq_disable()
> -> timer interrupt is raised in HW
> timer->expires = jiffies + 1 <- 1
> add_timer(timer)
> local_irq_enable()
> timer interrupt
> jiffies++;
> softirq()
> expire(timer); -> timer is expired immediately
>
> So the off by one has a reason and is required to prevent too short
> timeouts. There is nothing you can do about that because that's a
> property of low granularity tick based timer wheels.
>
> That's even documented in the comment above the code you modified:
>
> /*
> * The timer wheel has to guarantee that a timer does not fire
> * early. Early expiry can happen due to:
> * - Timer is armed at the edge of a tick
> * - Truncation of the expiry time in the outer wheel levels
> *
> * Round up with level granularity to prevent this.
> */

Thanks for your explanation. I got it !

Thanks,
Xiongfeng

>
> Thanks,
>
> tglx
> .
>