Re: [PATCH v3 3/3] riscv: optimized memset

[Nick Kossifidis]

Στις 2021-06-17 18:27, Matteo Croce έγραψε:
> +
> +void *__memset(void *s, int c, size_t count)
> +{
> +	union types dest = { .u8 = s };
> +
> +	if (count >= MIN_THRESHOLD) {
> +		const int bytes_long = BITS_PER_LONG / 8;

You could make 'const int bytes_long = BITS_PER_LONG / 8;' and 'const 
int mask = bytes_long - 1;' from your memcpy patch visible to memset as 
well (static const...) and use them here (mask would make more sense to 
be named as word_mask).

> +		unsigned long cu = (unsigned long)c;
> +
> +		/* Compose an ulong with 'c' repeated 4/8 times */
> +		cu |= cu << 8;
> +		cu |= cu << 16;
> +#if BITS_PER_LONG == 64
> +		cu |= cu << 32;
> +#endif
> +

You don't have to create cu here, you'll fill dest buffer with 'c' 
anyway so after filling up enough 'c's to be able to grab an aligned 
word full of them from dest, you can just grab that word and keep 
filling up dest with it.

> +#ifndef CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS
> +		/* Fill the buffer one byte at time until the destination
> +		 * is aligned on a 32/64 bit boundary.
> +		 */
> +		for (; count && dest.uptr % bytes_long; count--)

You could reuse & mask here instead of % bytes_long.

> +			*dest.u8++ = c;
> +#endif

I noticed you also used CONFIG_HAVE_EFFICIENT_UNALIGNED_ACCESS on your 
memcpy patch, is it worth it here ? To begin with riscv doesn't set it 
and even if it did we are talking about a loop that will run just a few 
times to reach the alignment boundary (worst case scenario it'll run 7 
times), I don't think we gain much here, even for archs that have 
efficient unaligned access.