Hi,Probably No.
On Mon, Jul 4, 2022 at 11:57 AM Vijaya Krishna Nivarthi (Temp)
<vnivarth@xxxxxxxxxxxxxxxx> wrote:
Hi,No. As you say, freq >= "mult-offset". That means that freq could be
-----Original Message-----Wouldn’t DIV_ROUND_UP(freq, desired_clk) suffice here?
From: Doug Anderson <dianders@xxxxxxxxxxxx>
Sent: Friday, July 1, 2022 8:38 PM
To: Vijaya Krishna Nivarthi (Temp) (QUIC) <quic_vnivarth@xxxxxxxxxxx>
Cc: Andy Gross <agross@xxxxxxxxxx>; bjorn.andersson@xxxxxxxxxx; Konrad
Dybcio <konrad.dybcio@xxxxxxxxxxxxxx>; Greg Kroah-Hartman
<gregkh@xxxxxxxxxxxxxxxxxxx>; Jiri Slaby <jirislaby@xxxxxxxxxx>; linux-arm-
msm <linux-arm-msm@xxxxxxxxxxxxxxx>; linux-serial@xxxxxxxxxxxxxxx; LKML
<linux-kernel@xxxxxxxxxxxxxxx>; Mukesh Savaliya (QUIC)
<quic_msavaliy@xxxxxxxxxxx>; Matthias Kaehlcke <mka@xxxxxxxxxxxx>;
Stephen Boyd <swboyd@xxxxxxxxxxxx>
Subject: Re: [V2] tty: serial: qcom-geni-serial: Fix get_clk_div_rate() which
otherwise could return a sub-optimal clock rate.
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Hi,
On Fri, Jul 1, 2022 at 4:04 AM Vijaya Krishna Nivarthi (Temp) (QUIC)
<quic_vnivarth@xxxxxxxxxxx> wrote:
Hi,<swboyd@xxxxxxxxxxxx>
-----Original Message-----
From: Doug Anderson <dianders@xxxxxxxxxxxx>
Sent: Thursday, June 30, 2022 4:45 AM
To: Vijaya Krishna Nivarthi (Temp) (QUIC)
<quic_vnivarth@xxxxxxxxxxx>
Cc: Andy Gross <agross@xxxxxxxxxx>; bjorn.andersson@xxxxxxxxxx;
Konrad Dybcio <konrad.dybcio@xxxxxxxxxxxxxx>; Greg Kroah-Hartman
<gregkh@xxxxxxxxxxxxxxxxxxx>; Jiri Slaby <jirislaby@xxxxxxxxxx>;
linux-arm- msm <linux-arm-msm@xxxxxxxxxxxxxxx>;
linux-serial@xxxxxxxxxxxxxxx; LKML <linux-kernel@xxxxxxxxxxxxxxx>;
Mukesh Savaliya (QUIC) <quic_msavaliy@xxxxxxxxxxx>; Matthias
Kaehlcke <mka@xxxxxxxxxxxx>; Stephen Boyd
*/Subject: Re: [V2] tty: serial: qcom-geni-serial: Fix
get_clk_div_rate() which otherwise could return a sub-optimal clock rate.
+ /* Save the first (lowest freq) within tolerance */
+ ser_clk = freq;
+ *clk_div = new_div;
+ /* no more search for exact match required in 2nd run
changes, and it seemed like what we need.I went back to your proposed algorithm and made couple of simple+ if (!exact_match)Can't you infinite loop now?
+ break;
+ }
+ }
- prev = freq;
+ div = freq / desired_clk + 1;
Start with:
desired_clk = 10000
div = 1
percent_tol = 2
Now:
mult = 10000
offset = 200
test_freq = 9800
freq = 9800
div = 9800 / 10000 + 1 = 0 + 1 = 1
...and then you'll loop again with "div = 1", won't you? ...or did I
get something wrong in my analysis? This is the reason my proposed
algorithm had two loops.
a) look only for exact match once a clock rate within tolerance isThe more I've been thinking about it, the more I wonder if we even need the
found
b) swap test_freq and freq at end of while loops to make it run as
desired
maxdiv = CLK_DIV_MSK >> CLK_DIV_SHFT;
div = 1;
while (div < maxdiv) {
mult = (unsigned long long)div * desired_clk;
if (mult != (unsigned long)mult)
break;
if (ser_clk)
offset = 0;
===================a=====================
else
offset = div_u64(mult * percent_tol, 100);
/*
* Loop requesting (freq - 2%) and possibly (freq).
*
* We'll keep track of the lowest freq inexact match we found
* but always try to find a perfect match. NOTE: this algorithm
* could miss a slightly better freq if there's more than one
* freq between (freq - 2%) and (freq) but (freq) can't be made
* exactly, but that's OK.
*
* This absolutely relies on the fact that the Qualcomm clock
* driver always rounds up.
*/
test_freq = mult - offset;
while (test_freq <= mult) {
freq = clk_round_rate(clk, test_freq);
/*
* A dead-on freq is an insta-win. This implicitly
* handles when "freq == mult"
*/
if (!(freq % desired_clk)) {
*clk_div = freq / desired_clk;
return freq;
}
/*
* Only time clock framework doesn't round up is if
* we're past the max clock rate. We're done searching
* if that's the case.
*/
if (freq < test_freq)
return ser_clk;
/* Save the first (lowest freq) within tolerance */
if (!ser_clk && freq <= mult + offset) {
ser_clk = freq;
*clk_div = div;
}
/*
* If we already rounded up past mult then this will
* cause the loop to exit. If not then this will run
* the loop a second time with exactly mult.
*/
test_freq = max(test_freq + 1, mult);
====b====
}
/*
* freq will always be bigger than mult by at least 1.
* That means we can get the next divider with a DIV_ROUND_UP.
* This has the advantage of skipping by a whole bunch of divs
* If the clock framework already bypassed them.
*/
div = DIV_ROUND_UP(freq, desired_clk);
===b==
}
Will also drop exact_match now.
Will upload v3 after testing.
special case of looking for an exact match at all. It feels like we should choose
one: we either look for the best match or we look for the one with the
lowest clock source rate. The weird half-half approach that we have right
now feels like over-engineering and complicates things.
How about this (again, only lightly tested). Worst case if we _truly_ need a
close-to-exact match we could pass a tolerance of 0 in and we'd get
something that's nearly exact, though I'm not suggesting we actually do that.
If we think 2% is good enough then we should just accept the first (and
lowest clock rate) 2% match we find.
abs_tol = div_u64((u64)desired_clk * percent_tol, 100);
maxdiv = CLK_DIV_MSK >> CLK_DIV_SHFT;
div = 1;
while (div <= maxdiv) {
mult = (u64)div * desired_clk;
if (mult != (unsigned long)mult)
break;
offset = div * abs_tol;
freq = clk_round_rate(clk, mult - offset);
/* Can only get lower if we're done */
if (freq < mult - offset)
break;
/*
* Re-calculate div in case rounding skipped rates but we
* ended up at a good one, then check for a match.
*/
div = DIV_ROUND_CLOSEST(freq, desired_clk);
achieved = DIV_ROUND_CLOSEST(freq, div);
if (achieved <= desired_clk + abs_tol &&
achieved >= desired_clk - abs_tol) {
*clk_div = div;
return freq;
}
/*
* Always increase div by at least one, but we'll go more than
* one if clk_round_rate() gave us something higher.
*/
div = DIV_ROUND_UP(max(freq, (unsigned long)mult) + 1, desired_clk);
freq >= mult-offset, else we would have hit break.
== "mult-offset", right? If offset > 0 then freq could be < mult. Then
your DIV_ROUND_UP() would just take you right back to where you
started the loop with and you'd end up with an infinite loop, wouldn't
you?
Additionally if freq <= mult we would have hit return.I thought about it and I decided that it might not if the clock
So always freq > mult?
And hence div++ would do the same?
framework skipped a whole bunch. Let's see if I can give an example.
Let's say
* "desired_clk" is 10000
* "percent_tol" is 2 (abs_tol = 200)
* We can make clocks 17000, 20000, 25000.
First time through the loop:
mult = 10000
offset = 200
freq = 17000
div = 2
achieved = 8500 (not within tolerance)
...at the end of the loop if we do "div++" then we'll end up with
div=3 for the next loop and we'll miss finding 20000.
...but if we do my math, we end up with:
DIV_ROUND_UP(max(17000, 10000) + 1, 10000)
DIV_ROUND_UP(17000 + 1, 10000)
DIV_ROUND_UP(17000, 10000)
2
...and that's exactly what we want.
Here's an example showing why the line "div = DIV_ROUND_CLOSEST(freq,
desired_clk)" is important:
* "desired_clk" is 10000
* "percent_tol" is 2 (abs_tol = 200)
* We can make clocks 19600, 25000.
mult = 10000
offset = 200
freq = 19600
div = 2
achieved = 9800
Returns 19600 and div=2
Here's an example showing how the clock framework rounding lets us
skip some "div"s without missing anything important:
* "desired_clk" is 10000
* "percent_tol" is 2 (abs_tol = 200)
* We can make clocks 24000, 30000.
mult = 25000
offset = 200
freq = 24000
div = 2
achieved = 12000 (not within tolerance)
div = DIV_ROUND_UP(max(24000, 10000) + 1, 10000)
div = 3
mult = 30000
offset = 600
freq = 30000
div = 3
-Doug