On Mon, Aug 8, 2022 at 4:41 AM Matthew Wilcox (Oracle)
<willy@xxxxxxxxxxxxx> wrote:
From: Kent Overstreet <kent.overstreet@xxxxxxxxx>
Like the upcoming vsprintf.c conversion, this converts string_escape_mem
to prt_escaped_string(), which uses and outputs to a printbuf, and makes
string_escape_mem() a smaller wrapper to support existing users.
The new printbuf helpers greatly simplify the code.
...
struct device;
struct file;
struct task_struct;
+struct printbuf;
Keep it ordered?
...
@@ -71,6 +74,7 @@ static inline int string_escape_mem_any_np(const char *src, size_t isz,
return string_escape_mem(src, isz, dst, osz, ESCAPE_ANY_NP, only);
}
+
static inline int string_escape_str(const char *src, char *dst, size_t sz,
unsigned int flags, const char *only)
{
Stray change.
...
if (!(is_append || in_dict) && is_dict &&
- escape_passthrough(c, &p, end))
+ escape_passthrough(out, c))
That (a bit strange) indentation is on purpose. Can we keep it?
continue;
...
Not sure if the below was in the original text, but maybe it makes
sense to amend.
+ * Description:
+ * The process of escaping byte buffer includes several parts. They are applied
a byte in the buffer (?)
+ * in the following sequence.
+ *
+ * 1. The character is not matched to the one from @only string and thus
+ * must go as-is to the output.
+ * 2. The character is matched to the printable and ASCII classes, if asked,
+ * and in case of match it passes through to the output.
+ * 3. The character is matched to the printable or ASCII class, if asked,
+ * and in case of match it passes through to the output.
+ * 4. The character is checked if it falls into the class given by @flags.
+ * %ESCAPE_OCTAL and %ESCAPE_HEX are going last since they cover any
+ * character. Note that they actually can't go together, otherwise
+ * %ESCAPE_HEX will be ignored.
+ *
+ * Caller must provide valid source and destination pointers. Be aware that
+ * destination buffer will not be NULL-terminated, thus caller have to append
the caller has