Re: [PATCH v7 00/11] kallsyms: Optimizes the performance of lookup symbols

[Leizhen (ThunderTown)]

On 2022/10/31 12:55, Leizhen (ThunderTown) wrote:
> 
> 
> On 2022/10/29 16:10, Leizhen (ThunderTown) wrote:
>>
>>
>> On 2022/10/27 14:27, Leizhen (ThunderTown) wrote:
>>>
>>>
>>> On 2022/10/27 11:26, Leizhen (ThunderTown) wrote:
>>>>
>>>>
>>>> On 2022/10/27 3:03, Luis Chamberlain wrote:
>>>>> On Wed, Oct 26, 2022 at 02:44:36PM +0800, Leizhen (ThunderTown) wrote:
>>>>>> On 2022/10/26 1:53, Luis Chamberlain wrote:
>>>>>>> This answers how we don't use a hash table, the question was *should* we
>>>>>>> use one?
>>>>>>
>>>>>> I'm not the original author, and I can only answer now based on my understanding. Maybe
>>>>>> the original author didn't think of the hash method, or he has weighed it out.
>>>>>>
>>>>>> Hash is a good solution if only performance is required and memory overhead is not
>>>>>> considered. Using hash will increase the memory size by up to "4 * kallsyms_num_syms +
>>>>>> 4 * ARRAY_SIZE(hashtable)" bytes, kallsyms_num_syms is about 1-2 million.
>>>
>>> Sorry, 1-2 million ==> 0.1~0.2 million
>>>
>>>>>>
>>>>>> Because I don't know what hash algorithm will be used, the cost of generating the
>>>>>> hash value corresponding to the symbol name is unknown now. But I think it's gonna
>>>>>> be small. But it definitely needs a simpler algorithm, the tool needs to implement
>>>>>> the same hash algorithm.
>>>>>
>>>>> For instance, you can look at evaluating if alloc_large_system_hash() would help.
>>>>
>>
>> The following three hash algorithms are compared. The kernel is compiled by defconfig
>> on arm64.
>>
>> |---------------------------------------------------------------------------------------|
>> |                           |             hash &= HASH_TABLE_SIZE - 1                   |
>> |                           |             number of conflicts >= 1000                   |
>> |---------------------------------------------------------------------------------------|
>> |   ARRAY_SIZE(hash_table)  |       crc16        | jhash_one_at_a_time | string hash_32 |
>> |---------------------------------------------------------------------------------------|
>> |                           |     345b: 3905     |     0d40: 1013      |   4a4c: 6548   |
>> |                           |     35bb: 1016     |     35ce: 6549      |   883a: 1015   |
>> |        0x10000            |     385b: 6548     |     4440: 19126     |   d05f: 19129  |
>> |                           |     f0ba: 19127    |     7ebe: 3916      |   ecda: 3903   |
>> |---------------------------------------------------------------------------------------|
>> |                           |      0ba: 19168    |      440: 19165     |    05f: 19170  |
>> |                           |      45b: 3955     |      5ce: 6577      |    83a: 1066   |
>> |        0x1000             |      5bb: 1069     |      d40: 1052      |    a4c: 6609   |
>> |                           |      85b: 6582     |      ebe: 3938      |    cda: 3924   |
>> |---------------------------------------------------------------------------------------|
>>
>> Based on the above test results, I conclude that:
>> 1. For the worst-case scenario, the three algorithms are not much different. But the kernel
>>    only implements crc16 and string hash_32. The latter is not processed byte-by-byte, so
>>    it is coupled with byte order and sizeof(long). So crc16 is the best choice.
>> 2. For the worst-case scenario, there are almost 19K strings are mapped to the same hash
>>    value，just over 1/10 of the total. And with my current compression-then-comparison
>>    approach, it's 25-30 times faster. So there's still a need for my current approach, and
>>    they can be combined.
>>    if (nr_conflicts(key) >= CONST_N) {
>>        newname = compress(name);
>>        for_each_name_in_slot(key): compare(new_name)
>>    } else {
>>        for_each_name_in_slot(key): compare(name)
>>    }
>>
>>    Above CONST_N can be roughly calculated:
>>    time_of_compress(name) + N * time_of_compare(new_name) <= N * time_of_compare(name)
>> 3. For the worst-case scenario, there is no obvious difference between ARRAY_SIZE(hash_table)
>>    0x10000 and 0x1000. So ARRAY_SIZE(hash_table)=0x1000 is enough.
>>    Statistic information:
>>    |------------------------------------------------------|
>>    |   nr_conflicts(key)  |     ARRAY_SIZE(hash_table)    |
>>    |------------------------------------------------------|
>>    |         <= ?         |     0x1000    |    0x10000    |
>>    |------------------------------------------------------|
>>    |             0        |         0     |      7821     |
>>    |            20        |        19     |     57375     |
>>    |            40        |      2419     |       124     |
>>    |            60        |      1343     |        70     |
>>    |            80        |       149     |        73     |
>>    |           100        |        38     |        49     |
>>    |           200        |       108     |        16     |
>>    |           400        |        14     |         2     |
>>    |           600        |         2     |         2     |
>>    |           800        |         0     |         0     |
>>    |          1000        |         0     |         0     |
>>    |        100000        |         4     |         4     |
>>    |------------------------------------------------------|
>>
>>
>> Also, I re-calculated:
>> Using hash will increase the memory size by up to "6 * kallsyms_num_syms + 4 * ARRAY_SIZE(hashtable)"
>>                                                    |---- What I said earlier was 4
>> The increased size is close to 1 MB if CONFIG_KALLSYMS_ALL=y.
>>
>> Hi, Luis:
>>   For the reasons of the above-mentioned second conclusion. And except for patches 4-6,
>> even if only the hash method is used, other patches and option "--lto-clang" in patch 6/11
>> are also needed. If you don't mind, I'd like to use hash at the next stage. The current
>> patch set is already huge.
> 
> I just had an update in response to David Laight's email. The hash solution is like
> a centrist. It doesn't seem very feasible.
> 
> Now, we need to make a decision. Choose one of the two:
> 1. Continue with my current approach. Improve the average performance of
>    kallsyms_lookup_name() by 20 to 30 times. The memory overhead is increased by:
>    arm64 (defconfig):
>      73.5KiB and 4.0% if CONFIG_KALLSYMS_ALL=y.
>      19.8KiB and 2.8% if CONFIG_KALLSYMS_ALL=n.
>    x86 (defconfig):
>      49.0KiB and 3.0% if CONFIG_KALLSYMS_ALL=y.
>      16.8KiB and 2.3% if CONFIG_KALLSYMS_ALL=n.
> 2. Sort names, binary search (The static function causes duplicate names. Additional work is required）
>    2^18=262144, only up to 18 symbol expansions and comparisons are required.
>    The performance is definitely excellent, although I haven't tested it yet.
>    The memory overhead is increased by: 6 * kallsyms_num_syms
>    arm64 (defconfig):
>        1MiB if CONFIG_KALLSYMS_ALL=y.
>      362KiB if CONFIG_KALLSYMS_ALL=n.
>    x86 (defconfig):
>      770KiB if CONFIG_KALLSYMS_ALL=y.
>      356KiB if CONFIG_KALLSYMS_ALL=n.
> 

Preliminary Test Results: (On Qemu arm64)
[   73.049249] kallsyms_selftest: kallsyms_lookup_name() looked up 151880 symbols
[   73.049331] kallsyms_selftest: The time spent on each symbol is (ns): min=1088, max=46848, avg=6629

> 
> 
> 
>>
>>
>>>> OK, I found the right hash function. In this way, the tool does not need to consider
>>>> the byte order.
>>>
>>> https://en.wikipedia.org/wiki/Jenkins_hash_function
>>>
>>> Let's go with jenkins_one_at_a_time_hash(), which looks simpler and doesn't even
>>> have to think about sizeof(long). It seems to be closest to our current needs.
>>>
>>> uint32_t jenkins_one_at_a_time_hash(const uint8_t* key, size_t length) {
>>> 	size_t i = 0;
>>> 	uint32_t hash = 0;
>>>
>>> 	while (i != length) {
>>> 		hash += key[i++];
>>> 		hash += hash << 10;
>>> 		hash ^= hash >> 6;
>>> 	}
>>> 	hash += hash << 3;
>>> 	hash ^= hash >> 11;
>>> 	hash += hash << 15;
>>>
>>> 	return hash;
>>> }
>>>
>>>>
>>>> include/linux/stringhash.h
>>>>
>>>> /*
>>>>  * Version 1: one byte at a time.  Example of use:
>>>>  *
>>>>  * unsigned long hash = init_name_hash;
>>>>  * while (*p)
>>>>  *      hash = partial_name_hash(tolower(*p++), hash);
>>>>  * hash = end_name_hash(hash);
>>>>
>>>>
>>>>>
>>>>>   Luis
>>>>> .
>>>>>
>>>>
>>>
>>
> 

-- 
Regards,
  Zhen Lei