rtla osnoise hist: average duration is always zero

[Andreas Ziegler]

-- Observed in, but not limited to, Linux 6.1.1

Dear all,

rtla osnoise hist always outputs '0' as average duration value. Example:

# rtla osnoise hist -P F:1 -c 0-1 -r 900000 -d 1M -b 1 -E 5000 -T 1
# RTLA osnoise histogram
# Time unit is microseconds (us)
# Duration:   0 00:01:00
  ...
count:     5629      1364
min:          1         1
avg:          0         0
max:       2955        56

This is due to sum_sample in osnoise_hist_update_multiple() being 
calculated as the sum (duration), not as sum (duration * count).

Rounding, instead of truncating, of the average value would be cool.

The following patch would solve the issue described above:


Sampled duration must be weighted by observed quantity, to arrive at a
correct average duration value.

Fix calculation of total duration by summing (duration * count).
Introduce rounding for calculation of final value.

Signed-off-by: Andreas Ziegler <br015@xxxxxxxxxx>

--- a/tools/tracing/rtla/src/osnoise_hist.c
+++ b/tools/tracing/rtla/src/osnoise_hist.c
@@ -121,6 +121,7 @@
 {
 	struct osnoise_hist_params *params = tool->params;
 	struct osnoise_hist_data *data = tool->data;
+	unsigned long long total_duration;
 	int entries = data->entries;
 	int bucket;
 	int *hist;
@@ -131,10 +132,12 @@
 	if (data->bucket_size)
 		bucket = duration / data->bucket_size;

+	total_duration = duration * count;
+
 	hist = data->hist[cpu].samples;
 	data->hist[cpu].count += count;
 	update_min(&data->hist[cpu].min_sample, &duration);
-	update_sum(&data->hist[cpu].sum_sample, &duration);
+	update_sum(&data->hist[cpu].sum_sample, &total_duration);
 	update_max(&data->hist[cpu].max_sample, &duration);

 	if (bucket < entries)
@@ -333,7 +336,7 @@

 		if (data->hist[cpu].count)
 			trace_seq_printf(trace->seq, "%9llu ",
-					data->hist[cpu].sum_sample / data->hist[cpu].count);
+				(data->hist[cpu].sum_sample + data->hist[cpu].count / 2) / 
data->hist[cpu].count);
 		else
 			trace_seq_printf(trace->seq, "        - ");
 	}


Kind regards,
Andreas