Re: [bug-report] possible s64 overflow in max_vruntime()

[Vincent Guittot]

On Tue, 7 Feb 2023 at 20:37, Roman Kagan <rkagan@xxxxxxxxx> wrote:
>
> On Tue, Jan 31, 2023 at 12:10:29PM +0100, Vincent Guittot wrote:
> > On Tue, 31 Jan 2023 at 11:00, Roman Kagan <rkagan@xxxxxxxxx> wrote:
> > > On Tue, Jan 31, 2023 at 11:21:17AM +0800, Chen Yu wrote:
> > > > On 2023-01-27 at 17:18:56 +0100, Vincent Guittot wrote:
> > > > > On Fri, 27 Jan 2023 at 12:44, Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
> > > > > >
> > > > > > On Thu, Jan 26, 2023 at 07:31:02PM +0100, Roman Kagan wrote:
> > > > > >
> > > > > > > > All that only matters for small sleeps anyway.
> > > > > > > >
> > > > > > > > Something like:
> > > > > > > >
> > > > > > > >         sleep_time = U64_MAX;
> > > > > > > >         if (se->avg.last_update_time)
> > > > > > > >           sleep_time = cfs_rq_clock_pelt(cfs_rq) - se->avg.last_update_time;
> > > > > > >
> > > > > > > Interesting, why not rq_clock_task(rq_of(cfs_rq)) - se->exec_start, as
> > > > > > > others were suggesting?  It appears to better match the notion of sleep
> > > > > > > wall-time, no?
> > > > > >
> > > > > > Should also work I suppose. cfs_rq_clock takes throttling into account,
> > > > > > but that should hopefully also not be *that* long, so either should
> > > > > > work.
> > > > >
> > > > > yes rq_clock_task(rq_of(cfs_rq)) should be fine too
> > > > >
> > > > > Another thing to take into account is the sleeper credit that the
> > > > > waking task deserves so the detection should be done once it has been
> > > > > subtracted from vruntime.
> > > > >
> > > > > Last point, when a nice -20 task runs on a rq, it will take a bit more
> > > > > than 2 seconds for the vruntime to be increased by more than 24ms (the
> > > > > maximum credit that a waking task can get) so threshold must be
> > > > > significantly higher than 2 sec. On the opposite side, the lowest
> > > > > possible weight of a cfs rq is 2 which means that the problem appears
> > > > > for a sleep longer or equal to 2^54 = 2^63*2/1024. We should use this
> > > > > value instead of an arbitrary 200 days
> > > > Does it mean any threshold between 2 sec and 2^54 nsec should be fine? Because
> > > > 1. Any task sleeps longer than 2 sec will get at most 24 ms(sysctl_sched_latency)
> > > >    'vruntime bonus' when enqueued.
> >
> > This means that if a task nice -20 runs on cfs rq while your task is
> > sleeping 2seconds, the min vruntime of the cfs rq will increase by
> > 24ms. If there are 2 nice -20 tasks then the min vruntime will
> > increase by 24ms after 4 seconds and so on ...
> >
> > On the other side, a task nice 19 that runs 1ms will increase its
> > vruntime by around 68ms.
> >
> > So if there is 1 task nice 19 with 11 tasks nice -20 on the same cfs
> > rq, the nice -19 one should run 1ms every 65 seconds and this also
> > means that the vruntime of task nice -19 should still be above
> > min_vruntime after sleeping 60 seconds. Of course this is even worse
> > with a child cgroup with the lowest weight (weight of 2 instead of 15)
> >
> > Just to say that 60 seconds is not so far away and 2^54 should be better IMHO
>
> If we go this route, what would be the proper way to infer this value?
> Looks like
>
>   (1ull << 63) / NICE_0_LOAD * scale_load(MIN_SHARES)

(1ull << 63) / NICE_0_LOAD * MIN_SHARES

>
> Is there any other definition that stipulates the lowest weight to be 2?

no, at task level the min weight is 3 for sched idle task.

> Besides, MIN_SHARES is under #ifdef CONFIG_FAIR_GROUP_SCHED, so the
> above expression would require more #ifdef-s.

(1ull << 63) / NICE_0_LOAD
could be a reasonable shortcut I think

>
> (That said, I'm still not convinced being math-precise here is
> practical, and slightly violating fairness in such a skewed setup is
> really something to be afraid of.)

We regularly have people complaining that sched_idle tasks (with a
weight of 3) wake up too often and steal time. The 60 seconds may just
make the situation happen more frequently

Vincent
>
> Thanks,
> Roman.
>
>
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