[PATCH] sched: report correct state for TASK_IDLE | TASK_FREEZABLE

From: NeilBrown
Date: Tue Aug 29 2023 - 19:05:41 EST



task_state_index() ignores uninteresting state flags (such as
TASK_FREEZABLE) for most states, but for TASK_IDLE and TASK_RTLOCK_WAIT
it does not.
So if a task is waiting TASK_IDLE|TASK_FREEZABLE it gets incorrectly
reported as TASK_UNINTERRUPTIBLE or "D". (it is planned for nfsd to
change to use this state).

Fix this by only testing the interesting bits and not the irrelevant
bits in __task_state_index()

Signed-off-by: NeilBrown <neilb@xxxxxxx>
---
include/linux/sched.h | 4 ++--
1 file changed, 2 insertions(+), 2 deletions(-)

diff --git a/include/linux/sched.h b/include/linux/sched.h
index 177b3f3676ef..c0a21a3b106c 100644
--- a/include/linux/sched.h
+++ b/include/linux/sched.h
@@ -1671,7 +1671,7 @@ static inline unsigned int __task_state_index(unsigned int tsk_state,

BUILD_BUG_ON_NOT_POWER_OF_2(TASK_REPORT_MAX);

- if (tsk_state == TASK_IDLE)
+ if ((tsk_state & TASK_IDLE) == TASK_IDLE)
state = TASK_REPORT_IDLE;

/*
@@ -1679,7 +1679,7 @@ static inline unsigned int __task_state_index(unsigned int tsk_state,
* to userspace, we can make this appear as if the task has gone through
* a regular rt_mutex_lock() call.
*/
- if (tsk_state == TASK_RTLOCK_WAIT)
+ if (tsk_state & TASK_RTLOCK_WAIT)
state = TASK_UNINTERRUPTIBLE;

return fls(state);
--
2.41.0