On Wed, Aug 30, 2023 at 03:25:54PM -0400, Azeem Shaikh wrote:
On Wed, Aug 30, 2023 at 1:57 PM Greg Kroah-Hartman
<gregkh@xxxxxxxxxxxxxxxxxxx> wrote:
On Wed, Aug 30, 2023 at 04:04:10PM +0000, Azeem Shaikh wrote:
strlcpy() reads the entire source buffer first.
This read may exceed the destination size limit if
a source string is not NUL-terminated [1].
But that's not the case here, right? So your "potential read overflow"
isn't relevant here.
The copy_to_user() call uses @len returned from strlcpy() directly
without checking its value. This could potentially lead to read
overflow.
But can it? How?
The case I was considering is when the null-terminated hardcoded
string @func_table[kb_func] has length @new_len > @len. In this case,
strlcpy() will assign @len = @new_len and copy_to_user() would read
@new_len from the kmalloc-ed memory of @len. This is the potential
read overflow I was referring to. Let me know if I'm mistaken.
First there is:
ssize_t len = sizeof(user_kdgkb->kb_string);
"struct user_kdgkb" is UAPI (therefore unlikely to change), and kb_string
is 512:
struct kbsentry {
unsigned char kb_func;
unsigned char kb_string[512];
};
Then we do:
len = strlcpy(kbs, func_table[kb_func] ? : "", len);
This is the anti-pattern (take the length of the _source_) we need to
remove.
However, func_table[] is made up of either %NUL-terminated
strings:
char func_buf[] = {
'\033', '[', '[', 'A', 0,
'\033', '[', '[', 'B', 0,
...
char *func_table[MAX_NR_FUNC] = {
func_buf + 0,
func_buf + 5,
...
Or a NULL address itself. The ?: operator handles the NULL case, so
"len" can only ever be 0 through the longest string in func_buf. So it's
what I'd call "accidentally correct". i.e. it's using a fragile
anti-pattern, but in this case everything is hard-coded and less than
512.
Regardless, we need to swap for a sane pattern, which you've done. But
the commit log is misleading, so it needs some more detail. :)