Re: [PATCH] locking: Document that mutex_unlock() is non-atomic

[Peter Zijlstra]

On Thu, Nov 30, 2023 at 09:48:17PM +0100, Jann Horn wrote:
> I have seen several cases of attempts to use mutex_unlock() to release an
> object such that the object can then be freed by another task.
> My understanding is that this is not safe because mutex_unlock(), in the
> MUTEX_FLAG_WAITERS && !MUTEX_FLAG_HANDOFF case, accesses the mutex
> structure after having marked it as unlocked; so mutex_unlock() requires
> its caller to ensure that the mutex stays alive until mutex_unlock()
> returns.
> 
> If MUTEX_FLAG_WAITERS is set and there are real waiters, those waiters
> have to keep the mutex alive, I think; but we could have a spurious
> MUTEX_FLAG_WAITERS left if an interruptible/killable waiter bailed
> between the points where __mutex_unlock_slowpath() did the cmpxchg
> reading the flags and where it acquired the wait_lock.
> 
> (With spinlocks, that kind of code pattern is allowed and, from what I
> remember, used in several places in the kernel.)
> 
> If my understanding of this is correct, we should probably document this -
> I think such a semantic difference between mutexes and spinlocks is fairly
> unintuitive.

IIRC this is true of all sleeping locks, and I think completion was the
explcicit exception here, but it's been a while.


> index 78540cd7f54b..087716bfa7b2 100644
> --- a/Documentation/locking/mutex-design.rst
> +++ b/Documentation/locking/mutex-design.rst
> @@ -101,6 +101,12 @@ features that make lock debugging easier and faster:
>      - Detects multi-task circular deadlocks and prints out all affected
>        locks and tasks (and only those tasks).
>  
> +Releasing a mutex is not an atomic operation: Once a mutex release operation

Well, it very much is an atomic store-release. That is, I object to your
confusing use of atomic here :-)