Re: [PATCH 3/4 net-next] net: mana: add a function to spread IRQs per CPUs

From: Souradeep Chakrabarti
Date: Wed Jan 10 2024 - 04:09:50 EST


On Tue, Jan 09, 2024 at 03:28:59PM -0800, Yury Norov wrote:
> Hi Michael,
>
> So, I'm just a guy who helped to formulate the heuristics in an
> itemized form, and implement them using the existing kernel API.
> I have no access to MANA machines and I ran no performance tests
> myself.
>
> On Tue, Jan 09, 2024 at 07:22:38PM +0000, Michael Kelley wrote:
> > From: Souradeep Chakrabarti <schakrabarti@xxxxxxxxxxxxxxxxxxx> Sent: Tuesday, January 9, 2024 2:51 AM
> > >
> > > From: Yury Norov <yury.norov@xxxxxxxxx>
> > >
> > > Souradeep investigated that the driver performs faster if IRQs are
> > > spread on CPUs with the following heuristics:
> > >
> > > 1. No more than one IRQ per CPU, if possible;
> > > 2. NUMA locality is the second priority;
> > > 3. Sibling dislocality is the last priority.
> > >
> > > Let's consider this topology:
> > >
> > > Node 0 1
> > > Core 0 1 2 3
> > > CPU 0 1 2 3 4 5 6 7
> > >
> > > The most performant IRQ distribution based on the above topology
> > > and heuristics may look like this:
> > >
> > > IRQ Nodes Cores CPUs
> > > 0 1 0 0-1
> > > 1 1 1 2-3
> > > 2 1 0 0-1
> > > 3 1 1 2-3
> > > 4 2 2 4-5
> > > 5 2 3 6-7
> > > 6 2 2 4-5
> > > 7 2 3 6-7
> >
> > I didn't pay attention to the detailed discussion of this issue
> > over the past 2 to 3 weeks during the holidays in the U.S., but
> > the above doesn't align with the original problem as I understood
> > it. I thought the original problem was to avoid putting IRQs on
> > both hyper-threads in the same core, and that the perf
> > improvements are based on that configuration. At least that's
> > what the commit message for Patch 4/4 in this series says.
>
> Yes, and the original distribution suggested by Souradeep looks very
> similar:
>
> IRQ Nodes Cores CPUs
> 0 1 0 0
> 1 1 1 2
> 2 1 0 1
> 3 1 1 3
> 4 2 2 4
> 5 2 3 6
> 6 2 2 5
> 7 2 3 7
>
> I just added a bit more flexibility, so that kernel may pick any
> sibling for the IRQ. As I understand, both approaches have similar
> performance. Probably my fine-tune added another half-percent...
>
> Souradeep, can you please share the exact numbers on this?
>
> > The above chart results in 8 IRQs being assigned to the 8 CPUs,
> > probably with 1 IRQ per CPU. At least on x86, if the affinity
> > mask for an IRQ contains multiple CPUs, matrix_find_best_cpu()
> > should balance the IRQ assignments between the CPUs in the mask.
> > So the original problem is still present because both hyper-threads
> > in a core are likely to have an IRQ assigned.
>
> That's what I think, if the topology makes us to put IRQs in the
> same sibling group, the best thing we can to is to rely on existing
> balancing mechanisms in a hope that they will do their job well.
>
> > Of course, this example has 8 IRQs and 8 CPUs, so assigning an
> > IRQ to every hyper-thread may be the only choice. If that's the
> > case, maybe this just isn't a good example to illustrate the
> > original problem and solution.
>
> Yeah... This example illustrates the order of IRQ distribution.
> I really doubt that if we distribute IRQs like in the above example,
> there would be any difference in performance. But I think it's quite
> a good illustration. I could write the title for the table like this:
>
> The order of IRQ distribution for the best performance
> based on [...] may look like this.
>
> > But even with a better example
> > where the # of IRQs is <= half the # of CPUs in a NUMA node,
> > I don't think the code below accomplishes the original intent.
> >
> > Maybe I've missed something along the way in getting to this
> > version of the patch. Please feel free to set me straight. :-)
>
> Hmm. So if the number of IRQs is the half # of CPUs in the nodes,
> which is 2 in the example above, the distribution will look like
> this:
>
> IRQ Nodes Cores CPUs
> 0 1 0 0-1
> 1 1 1 2-3
>
> And each IRQ belongs to a different sibling group. This follows
> the rules above.
>
> I think of it like we assign an IRQ to a group of 2 CPUs, so from
> the heuristic #1 perspective, each CPU is assigned with 1/2 of the
> IRQ.
>
> If I add one more IRQ, then according to the heuristics, NUMA locality
> trumps sibling dislocality, so we'd assign IRO to the same node on any
> core. My algorithm assigns it to the core #0:
>
> 2 1 0 0-1
>
> This doubles # of IRQs for the CPUs 0 and 1: from 1/2 to 1.
>
> The next IRQ should be assigned to the same node again, and we've got
> the only choice:
>
>
> 3 1 1 2-3
>
> Starting from IRQ #5, the node #1 is full - each CPU is assigned with
> exactly one IRQ, and the heuristic #1 makes us to switch to the other
> node; and then do the same thing:
>
> 4 2 2 4-5
> 5 2 3 6-7
> 6 2 2 4-5
> 7 2 3 6-7
>
> So I think the algorithm is correct... Really hope the above makes
> sense. :) If so, I can add it to the commit message for patch #3.
>
> Nevertheless... Souradeep, in addition to the performance numbers, can
> you share your topology and actual IRQ distribution that gains 15%? I
> think it should be added to the patch #4 commit message.
Sure I will add my topology in #4 commit message. Thanks for the suggestion.
>
> Thanks,
> Yury