Re: [PATCH v2] sched/fair: Make SCHED_IDLE entity be preempted in strict hierarchy
From: Peter Zijlstra
Date: Mon Jul 08 2024 - 10:29:17 EST
On Mon, Jul 08, 2024 at 02:47:34PM +0200, Vincent Guittot wrote:
> On Mon, 8 Jul 2024 at 14:02, Peter Zijlstra <peterz@xxxxxxxxxxxxx> wrote:
> > > @@ -8409,6 +8400,15 @@ static void check_preempt_wakeup_fair(struct rq *rq, struct task_struct *p, int
> > > if (cse_is_idle != pse_is_idle)
> > > return;
> > >
> > > + /*
> > > + * Batch tasks do not preempt non-idle tasks (their preemption
> > > + * is driven by the tick).
> > > + * We've done the check about "only one of the entities is idle",
> > > + * so cse must be non-idle if p is a batch task.
> > > + */
> > > + if (unlikely(entity_is_task(pse) && p->policy == SCHED_BATCH))
> > > + return;
> >
> > I'm not convinced this condition is right. The current behaviour of
> > SCHED_BATCH doesn't care about pse, only p.
> >
> > That is, if p is SCHED_BATCH it will not preempt -- except an
> > SCHED_IDLE.
> >
> > So I'm tempted to delete this first part of your condition and have it
> > be:
> >
> > if (p->policy == SCHED_BATCH)
> > return;
> >
> > That is, suppose you have:
> >
> > root
> > |
> > ------------------------
> > | |
> > normal_cgroup normal_cgroup
> > | |
> > SCHED_BATCH task_A SCHED_BATCH task_B
> >
> > Then the preemption crud will end up comparing the groups to one another
> > and still allow A to preempt B -- except we explicitly do not want this.
> >
> > The 'problem' is that the whole BATCH thing isn't cgroup aware ofcourse,
> > but I'm not sure we want to go fix that -- esp. not in this patch.
> >
> > Hmm?
>
> Good question, but do we want to make SCHED_BATCH tasks behave
> differently than SCHED_IDLE tasks in a group in this case ?
I suspect we'll have to. People added the idle-cgroup thing, but never
did the same for batch. With the result that they're now fundamentally
different.
> With this patch, we don't want task_B to preempt task_A for the case
> but task_A will preempt task_B whereas task A is SCHED_IDLE
>
> root
> |
> ------------------------
> | |
> normal_cgroup idle_cgroup
> | |
> SCHED_IDLE task_A SCHED_NORMAL task_B
>
> As we only look at the common level of hierarchy between the tasks,
> the below will make A to preempt B whereas both are SCHED_IDLE
>
> root
> |
> ------------------------
> | |
> normal_cgroup normal_cgroup
> | |
> SCHED_IDLE task_A SCHED_IDLE task_B
So we can make the last test be:
if (unlikely(p->policy != SCHED_NORMAL))
return;
Much like the original condition removed here:
- if (unlikely(p->policy != SCHED_NORMAL) || !sched_feat(WAKEUP_PREEMPTION))
+ if (!sched_feat(WAKEUP_PREEMPTION))
Except now after all that cgroup nonsense. Then the OP case will preempt
because normal_cgroup vs idle_cgroup, my BATCH example will not preempt,
because BATCH != NORMAL, your IDLE example will not preempt either,
because IDLE != NORMAL.