Re: [PATCH 04/11] of: address: Preserve the flags portion on 1:1 dma-ranges mapping

From: Andrea della Porta
Date: Tue Sep 03 2024 - 12:15:15 EST


Hi Rob,

On 14:37 Fri 30 Aug , Rob Herring wrote:
> On Thu, Aug 29, 2024 at 11:26 AM Andrea della Porta
> <andrea.porta@xxxxxxxx> wrote:
> >
> > Hi Rob,
> >

...

>
> I think simple-bus where you have it is fine. It is really 1 level up
> that needs to be specified. Basically something that's referenced from
> the specific PCI device's schema (e.g. the RP1 schema (which you are
> missing)).
>
> That schema needs to roughly look like this:
>
> properties:
> "#address-cells":
> const: 3
> "#size-cells":
> const: 2
> ranges:
> minItems: 1
> maxItems: 6
> items:
> additionalItems: true
> items:
> - maximum: 5 # The BAR number
> - const: 0
> - const: 0
> - # TODO: valid PCI memory flags
>
> patternProperties:
> "^bar-bus@[0-5]$":
> type: object
> additionalProperties: true
> properties:
> compatible:
> const: simple-bus
> ranges: true
>

Hmmm.. not sure how this is going to work. The PCI device (RP1) will
havei, at runtime, a compatible like this:

compatible = "pci1de4,1\0pciclass,0200000\0pciclass,0200";

that is basically generated automatically by the OF framework. So, in the
schema you proposed above, I can put something like:

properties:
compatible:
contains:
pattern: '^pci1de4,1'

or maybe I could omit the compatible entirely, like in:

https://github.com/devicetree-org/dt-schema/blob/main/dtschema/schemas/pci/pci-iommu.yaml

that seems to refer to generic compatible values.
In both cases though, I don't see how these binding could work with
make dt_binding_check, since there's no compatible known at compile
time (for the first approach), or no compatible at all (the second
approach).
Is it intended only as a loose documentation?
Or are you proposing that for a future new bus (hence with a new, specific,
compatible) that could be described by the schema above?

Many thanks,
Andrea

> There were some discussions around interrupt handling that might also
> factor into this.
>
> Rob