Re: [RFC PATCH 1/4] hazptr: Add initial implementation of hazard pointers

[Alan Huang]

2024年9月20日 02:58，Boqun Feng <boqun.feng@xxxxxxxxx> wrote：
> 
> On Thu, Sep 19, 2024 at 09:57:12PM +0800, Alan Huang wrote:
> [...]
>>> 
>>> I think you're right. (Although the node will be eventually deleted at
>>> cleanup_hazptr_context(), however there could be a long-live
>>> hazptr_context). It should be:
>>> 
>>> hazptr_t val = smp_load_acquire(&hzcp->slots[i]);
>>> struct hazptr_slot_snap *snap = &hzcp->snaps[i];
>>> 
>>> if (val != snap->slot) { // val changed, need to update the tree node.
>>> // Already in the tree, need to remove first.
>>> if (!is_null_or_unused(snap->slot)) {
>>> reader_del(tree, snap);
>>> }
>>> 
>>> // use the latest snapshot.
>>> snap->slot = val;
>>> 
>>> // Add it into tree if there is a reader
>>> if (!is_null_or_unused(val))
>>> reader_add(tree, snap);
>>> }
>> 
>> It seems like that two different hazptr_context can’t be used to protect the same pointer?
>> 
>> Otherwise the following can happen?
>> 
>> thread1  thread2    thread3(worker)        thread4
>> hazptr_tryprotect(hzp1, ptr1)   hazptr_tryprotect(hzp2, ptr1) 
>>  add ptr1 to tree
> 
> Note that we have snapshot rb_node for each hazard pointer slot, so here
> thread3 actually would add two rb_nodes with ->slot == ptr1 here.

Ok, good to know the rbtree can have multiple nodes with the same key.

Thanks for the explanation!

> 
>> hazptr_clear(hzp1) 
>> hazptr_tryprotect(hzp1, ptr2) 
>>  delete ptr1 from tree     unpub ptr1
> 
> Therefore, there is still one rb_node with ->slot == ptr1 in the tree
> after the deletion, so updaters won't invoke ptr1's callback.
> 
> Regards,
> Boqun
> 
>>        call_hazptr(ptr1)
>>        oops: invoke ptr1's callback
>> Or am I missing something?
>> 
>>> 
>>> Regards,
>>> Boqun
>>> 
>>>> I'm not so sure...
>>>> 
>>>> Thanks
>>>> Lai