Re: [PATCH] smaps: count large pages smaller than PMD size to anonymous_thp
From: Ryan Roberts
Date: Wed Dec 04 2024 - 12:36:11 EST
On 04/12/2024 14:40, Wenchao Hao wrote:
> On 2024/12/3 22:42, Ryan Roberts wrote:
>> On 03/12/2024 14:17, David Hildenbrand wrote:
>>> On 03.12.24 14:49, Wenchao Hao wrote:
>>>> Currently, /proc/xxx/smaps reports the size of anonymous huge pages for
>>>> each VMA, but it does not include large pages smaller than PMD size.
>>>>
>>>> This patch adds the statistics of anonymous huge pages allocated by
>>>> mTHP which is smaller than PMD size to AnonHugePages field in smaps.
>>>>
>>>> Signed-off-by: Wenchao Hao <haowenchao22@xxxxxxxxx>
>>>> ---
>>>> fs/proc/task_mmu.c | 6 ++++++
>>>> 1 file changed, 6 insertions(+)
>>>>
>>>> diff --git a/fs/proc/task_mmu.c b/fs/proc/task_mmu.c
>>>> index 38a5a3e9cba2..b655011627d8 100644
>>>> --- a/fs/proc/task_mmu.c
>>>> +++ b/fs/proc/task_mmu.c
>>>> @@ -717,6 +717,12 @@ static void smaps_account(struct mem_size_stats *mss,
>>>> struct page *page,
>>>> if (!folio_test_swapbacked(folio) && !dirty &&
>>>> !folio_test_dirty(folio))
>>>> mss->lazyfree += size;
>>>> +
>>>> + /*
>>>> + * Count large pages smaller than PMD size to anonymous_thp
>>>> + */
>>>> + if (!compound && PageHead(page) && folio_order(folio))
>>>> + mss->anonymous_thp += folio_size(folio);
>>>> }
>>>> if (folio_test_ksm(folio))
>>>
>>>
>>> I think we decided to leave this (and /proc/meminfo) be one of the last
>>> interfaces where this is only concerned with PMD-sized ones:
>>>
>>> Documentation/admin-guide/mm/transhuge.rst:
>>>
>>> The number of PMD-sized anonymous transparent huge pages currently used by the
>>> system is available by reading the AnonHugePages field in ``/proc/meminfo``.
>>> To identify what applications are using PMD-sized anonymous transparent huge
>>> pages, it is necessary to read ``/proc/PID/smaps`` and count the AnonHugePages
>>> fields for each mapping. (Note that AnonHugePages only applies to traditional
>>> PMD-sized THP for historical reasons and should have been called
>>> AnonHugePmdMapped).
>>>
>>
>> Agreed. If you need per-process metrics for mTHP, we have a python script at
>> tools/mm/thpmaps which does a fairly good job of parsing pagemap. --help gives
>> you all the options.
>>
>
> I tried this tool, and it is very powerful and practical IMO.
> However, thereare two disadvantages:
>
> - This tool is heavily dependent on Python and Python libraries.
> After installing several libraries with the pip command, I was able to
> get it running.
I think numpy is the only package it uses which is not in the standard library?
What other libraries did you need to install?
> In practice, the environment we need to analyze may be a mobile or
> embedded environment, where it is very difficult to deploy these
> libraries.
Yes, I agree that's a problem, especially for Android. The script has proven
useful to me for debugging in a traditional Linux distro environment though.
> - It seems that this tool only counts file-backed large pages? During
No; the tool counts file-backed and anon memory. But it reports it in separate
counters. See `thpmaps --help` for full details.
> the actual test, I mapped a region of anonymous pages and mapped it
> as large pages, but the tool did not display those large pages.
> Below is my test file(mTHP related sysfs interface is set to "always"
> to make sure using large pages):
Which mTHP sizes did you enable? Depending on your value of SIZE and which mTHP
sizes are enabled, you may not have a correctly aligned region in p. So mTHP
would not be allocated. Best to over-allocate then explicitly align p to the
mTHP size, then fault it in.
>
> int main()
> {
> int i;
> char *c;
> unsigned long *p;
>
> p = mmap(NULL, SIZE, PROT_READ | PROT_WRITE, MAP_PRIVATE | MAP_ANONYMOUS, -1, 0);
What is SIZE here?
> if (!p) {
> perror("fail to get memory");
> exit(-1);
> }
>
> c = (unsigned char *)p;
>
> for (i = 0; i < SIZE / 8; i += 8)
> *(p + i) = 0xffff + i;
Err... what's your intent here? I think you're writting to 1 in every 8 longs?
Probably just write to the first byte of every page.
Thanks,
Ryan
>
> while (1)
> sleep(10);
>
> return 0;
> }
>
> Thanks,
> wenchao
>