Re: futex+io_uring: futex_q::task can maybe be dangling (but is not actually accessed, so it's fine)

From: Peter Zijlstra
Date: Mon Jan 13 2025 - 09:41:59 EST


On Fri, Jan 10, 2025 at 08:33:34PM -0700, Jens Axboe wrote:

> @@ -548,7 +549,7 @@ void __futex_queue(struct futex_q *q, struct futex_hash_bucket *hb)
>
> plist_node_init(&q->list, prio);
> plist_add(&q->list, &hb->chain);
> - q->task = current;
> + q->task = task;
> }
>
> /**

The alternative is, I suppose, to move the q->task assignment out to
these two callsites instead. Thomas, any opinions?

> @@ -303,7 +304,7 @@ extern int futex_unqueue(struct futex_q *q);
> static inline void futex_queue(struct futex_q *q, struct futex_hash_bucket *hb)
> __releases(&hb->lock)
> {
> - __futex_queue(q, hb);
> + __futex_queue(q, hb, current);
> spin_unlock(&hb->lock);
> }
>
> diff --git a/kernel/futex/pi.c b/kernel/futex/pi.c
> index d62cca5ed8f4..635c7d5d4222 100644
> --- a/kernel/futex/pi.c
> +++ b/kernel/futex/pi.c
> @@ -982,7 +982,7 @@ int futex_lock_pi(u32 __user *uaddr, unsigned int flags, ktime_t *time, int tryl
> /*
> * Only actually queue now that the atomic ops are done:
> */
> - __futex_queue(&q, hb);
> + __futex_queue(&q, hb, current);
>
> if (trylock) {
> ret = rt_mutex_futex_trylock(&q.pi_state->pi_mutex);
>
> --
> Jens Axboe