On Tue, Feb 25, 2025 at 04:54:54PM +0800, Ethan Zhao wrote:
Why does this happen? If the kernel has shutdown other CPUs then whatOn 2025/2/25 14:48, Yunhui Cui wrote:
We found that executing the command ./a.out &;reboot -f (where a.out
is a
program that only executes a while(1) infinite loop) can
probabilistically
cause the system to hang in the intel_iommu_shutdown() function,
rendering
it unresponsive. Through analysis, we identified that the factors
contributing to this issue are as follows:
1. The reboot -f command does not prompt the kernel to notify the
application layer to perform cleanup actions, allowing the
application to
continue running.
2. When the kernel reaches the intel_iommu_shutdown() function, only the
BSP (Bootstrap Processor) CPU is operational in the system.
3. During the execution of intel_iommu_shutdown(), the function
down_write
(&dmar_global_lock) causes the process to sleep and be scheduled out.
thread is holding the other side of this lock and why?
If the schedular doesn't run how did we get from 4 -> 5?4. At this point, though the processor's interrupt flag is not cleared,
allowing interrupts to be accepted. However, only legacy devices
and NMI
(Non-Maskable Interrupt) interrupts could come in, as other interrupts
routing have already been disabled. If no legacy or NMI interrupts occur
at this stage, the scheduler will not be able to run.
5. If the application got scheduled at this time is executing a
while(1)-
type loop, it will be unable to be preempted, leading to an infinite
loop
and causing the system to become unresponsive.
Maybe the issue is the shutdown handler here is running in the wrong
time and it should not be running after the scheduler has been shut
down.
I don't think removing the lock is a great idea without more
explanation.
Jason