[PATCH] btrfs: return a literal instead of a variable

From: Dan Carpenter
Date: Wed Mar 05 2025 - 10:05:36 EST


This is just a small clean up, it doesn't change how the code works.
Originally this code had a goto so we needed to set "ret = 0;" but now
it returns directly and so we can simplify it a bit by doing a
"return 0;" and removing the assignment.

Signed-off-by: Dan Carpenter <dan.carpenter@xxxxxxxxxx>
---
fs/btrfs/dev-replace.c | 3 +--
1 file changed, 1 insertion(+), 2 deletions(-)

diff --git a/fs/btrfs/dev-replace.c b/fs/btrfs/dev-replace.c
index 1a82e88ec5c1..53d7d85cb4be 100644
--- a/fs/btrfs/dev-replace.c
+++ b/fs/btrfs/dev-replace.c
@@ -103,7 +103,6 @@ int btrfs_init_dev_replace(struct btrfs_fs_info *fs_info)
"found replace target device without a valid replace item");
return -EUCLEAN;
}
- ret = 0;
dev_replace->replace_state =
BTRFS_IOCTL_DEV_REPLACE_STATE_NEVER_STARTED;
dev_replace->cont_reading_from_srcdev_mode =
@@ -120,7 +119,7 @@ int btrfs_init_dev_replace(struct btrfs_fs_info *fs_info)
dev_replace->tgtdev = NULL;
dev_replace->is_valid = 0;
dev_replace->item_needs_writeback = 0;
- return ret;
+ return 0;
}
slot = path->slots[0];
eb = path->nodes[0];
--
2.47.2