Re: [PATCH] sched: Recheck the rt task's on rq state after double_lock_balance()

From: Tengfei Fan
Date: Sat Oct 25 2025 - 02:43:59 EST



On 10/20/2025 8:55 PM, 'Valentin Schneider' via kernel wrote:
On 09/10/25 00:23, Tengfei Fan wrote:
Recheck whether next_task is still in the runqueue of this_rq after
locking this_rq and lowest_rq via double_lock_balance() in
push_rt_task(). This is necessary because double_lock_balance() first
releases this_rq->lock and then attempts to acquire both this_rq->lock
and lowest_rq->lock, during which next_task may have already been
removed from this_rq's runqueue, leading to a double dequeue issue.

The double dequeue issue can occur in the following scenario:
1. Core0 call stack:
autoremove_wake_function
default_wake_function
try_to_wake_up
ttwu_do_activate
task_woken_rt
push_rt_task
move_queued_task_locked
dequeue_task
__wake_up

2. Execution flow on Core0, Core1 and Core2(Core0, Core1 and Core2 are
contending for Core1's rq->lock):
- Core1: enqueue next_task on Core1
- Core0: lock Core1's rq->lock
next_task = pick_next_pushable_task()
unlock Core1's rq->lock via double_lock_balance()
- Core1: lock Core1's rq->lock
next_task = pick_next_task()
unlock Core1's rq->lock
- Core2: lock Core1's rq->lock in migration thread
- Core1: running next_task
- Core2: unlock Core1's rq->lock
- Core1: lock Core1's rq->lock
switches out and dequeue next_task
unlock Core1's rq->lock
- Core0: relock Core1's rq->lock from double_lock_balance()
try to relock Core1's rq->lock from double_lock_balance()
but next_task has been dequeued from Core1, causing the issue

Signed-off-by: Tengfei Fan <tengfei.fan@xxxxxxxxxxxxxxxx>
---
kernel/sched/rt.c | 8 ++++++++
1 file changed, 8 insertions(+)

diff --git a/kernel/sched/rt.c b/kernel/sched/rt.c
index 7936d4333731..b4e44317a5de 100644
--- a/kernel/sched/rt.c
+++ b/kernel/sched/rt.c
@@ -2037,6 +2037,14 @@ static int push_rt_task(struct rq *rq, bool pull)
goto retry;
}
+ /* Within find_lock_lowest_rq(), it's possible to first unlock the
+ * rq->lock of the runqueue containing next_task, and the re->lock
+ * it. During this window, the state of next_task might have change.
+ */
+ if (unlikely(rq != task_rq(next_task) ||
+ !task_on_rq_queued(next_task)))
+ goto out;
+
Isn't this already covered by find_lock_lowest_rq()?

Yes, this logic is already included in find_lock_lowest_rq(). Previously, we were missing the following patch.

https://lore.kernel.org/r/20250225180553.167995-1-harshit@xxxxxxxxxxx

We will recheck whether our case has already been resolved by this patch.



if @next_task migrates during the double_lock_balance(), we'll see that
it's no longer the next highest priority pushable task of its original rq
(it won't be in that pushable list at all actually):

static struct rq *find_lock_lowest_rq(struct task_struct *task, struct rq *rq)
{
[...]
if (double_lock_balance(rq, lowest_rq)) {
if (unlikely(is_migration_disabled(task) ||
!cpumask_test_cpu(lowest_rq->cpu, &task->cpus_mask) ||
task != pick_next_pushable_task(rq))) {

double_unlock_balance(rq, lowest_rq);
lowest_rq = NULL;
break;
}
}
}

Plus:

static int push_rt_task(struct rq *rq, bool pull)
{
[...]
if (!lowest_rq) {
struct task_struct *task;
task = pick_next_pushable_task(rq);
[...]
put_task_struct(next_task);
next_task = task;
goto retry;
}
}

AFAICT in the scenario you described, we'd just retry with another next
pushable task.
I think this is just a different handling approach. At the time, our concern was that retrying might introduce an infinite loop.

move_queued_task_locked(rq, lowest_rq, next_task);
resched_curr(lowest_rq);
ret = 1;

---
base-commit: 7c3ba4249a3604477ea9c077e10089ba7ddcaa03
change-id: 20251008-recheck_rt_task_enqueue_state-e159aa6a2749

Best regards,
--
Tengfei Fan <tengfei.fan@xxxxxxxxxxxxxxxx>

--
Thx and BRs,
Tengfei Fan