Re: [PATCH 2/2] futex/requeue: Prevent rcuwait use-after-free during requeue PI
From: Yao Kai
Date: Sun Jul 19 2026 - 22:51:15 EST
On 7/17/2026 5:38 PM, Sebastian Andrzej Siewior wrote:
On 2026-07-17 16:49:22 [+0800], Yao Kai wrote:
On PREEMPT_RT, FUTEX_CMP_REQUEUE_PI can trigger a KASAN report:
BUG: KASAN: slab-out-of-bounds in _raw_spin_lock_irqsave+0x76/0xe0
Call Trace:
_raw_spin_lock_irqsave+0x76/0xe0
try_to_wake_up+0xab/0x1540
rcuwait_wake_up+0x39/0x60
futex_requeue+0x18c3/0x1e10
The futex_q used by futex_wait_requeue_pi() is allocated on the waiter's
stack. An early wakeup can race with a PI requeue as follows:
waiter requeue task
------ ------------
futex_wait_requeue_pi()
futex_do_wait()
schedule()
* timeout/signal wakes waiter *
futex_requeue_pi_wakeup_sync()
IN_PROGRESS -> WAIT
rcuwait_wait_event()
requeue_pi_wake_futex()
task = READ_ONCE(q->task)
futex_requeue_pi_complete()
WAIT -> LOCKED
return LOCKED
return
// q lifetime ends
rcuwait_wake_up()
futex_requeue_pi_complete() publishes LOCKED before calling
rcuwait_wake_up(). Once the waiter observes LOCKED, it can return from
futex_wait_requeue_pi() and let q go out of scope before rcuwait_wake_up()
reads q->requeue_wait.task and passes the stale pointer to
try_to_wake_up().
Skip rcuwait_wake_up() for Q_REQUEUE_PI_LOCKED. requeue_pi_wake_futex()
already saves q->task before publishing LOCKED and wakes the saved task
afterward.
Fixes: 07d91ef510fb1 ("futex: Prevent requeue_pi() lock nesting issue on RT")
Cc: stable@xxxxxxxxxxxxxxx
Signed-off-by: Yao Kai <yaokai34@xxxxxxxxxx>
---
kernel/futex/requeue.c | 9 +++++++--
1 file changed, 7 insertions(+), 2 deletions(-)
diff --git a/kernel/futex/requeue.c b/kernel/futex/requeue.c
index abc652b5b2dd..59e587775d9b 100644
--- a/kernel/futex/requeue.c
+++ b/kernel/futex/requeue.c
@@ -155,8 +155,13 @@ static inline void futex_requeue_pi_complete(struct futex_q *q, int locked)
} while (!atomic_try_cmpxchg(&q->requeue_state, &old, new));
#ifdef CONFIG_PREEMPT_RT
- /* If the waiter interleaved with the requeue let it know */
- if (unlikely(old == Q_REQUEUE_PI_WAIT))
+ /*
+ * If the waiter interleaved with the requeue, let it know. For LOCKED,
+ * q may already be invalid, so requeue_pi_wake_futex() wakes the saved
+ * task instead.
+ */
+ if (unlikely(old == Q_REQUEUE_PI_WAIT) &&
+ new != Q_REQUEUE_PI_LOCKED)
rcuwait_wake_up(&q->requeue_wait);
Your whole assumption is based on the requeue_state in
futex_requeue_pi_wakeup_sync() changes from Q_REQUEUE_PI_IN_PROGRESS to
Q_REQUEUE_PI_WAIT and the rcuwait_wait_event() does not wait because the
condition becomes true before that happens. So the rcuwait_wake_up()
could access q.requeue_wait which is allocated on behalf of the waiter
which is gone. Certainly possible. But if we skip the wait in thise case
we probably miss the 99% cases where the waiter did wait, no?
This looks similar to commit b549113738e8c ("futex: Prevent
use-after-free during requeue-PI").
#endif
}
Sebastian
No wakeup is missed. Q_REQUEUE_PI_LOCKED is only published by
requeue_pi_wake_futex(), which saves q->task before publishing the state
and calls wake_up_state(task, TASK_NORMAL) afterwards. The other
futex_requeue_pi_complete() callers produce DONE or an error state, and
the rcuwait wakeup is retained for those paths.
Thanks,
Yao