Re: [PATCH v19 03/14] KVM: arm64: Manage GCS access and registers for guests

From: Leonardo Bras

Date: Fri Aug 21 2026 - 07:26:35 EST


On Fri, Aug 21, 2026 at 12:39:08AM +0100, Wei-Lin Chang wrote:
> On Thu, Aug 20, 2026 at 03:28:39PM +0100, Leonardo Bras wrote:
> > On Thu, Aug 20, 2026 at 03:07:14PM +0100, Mark Brown wrote:
> > > On Thu, Aug 20, 2026 at 11:16:59AM +0100, Leonardo Bras wrote:
> > > > On Wed, Aug 19, 2026 at 05:46:00PM +0100, Mark Brown wrote:
> > >
> > > > > This is just because there isn't a preexisting ctxt_has_tcrx() check
> > > > > already there, FEAT_GCS architecturally depends on FEAT_TCRX and there
> > > > > was a request to make this explicit in the code to try to optimise
> > > > > things a bit. The compiler should skip over both blocks at once if TCRX
> > > > > isn't there rather than having two separate tests or static branches. I
> > > > > didn't add new checks where there were none since I expect that to be
> > > > > unhelpful for code generation, you'd get the reverse situation and emit
> > > > > two checks.
> > >
> > > > Humm, but then why saving GCSPR_EL2 does not depend on TCRX/E2H? Or maybe a
> > > > better question, why are not GCSPR_EL2 and GCSCR_EL2 saved in the same 'if'
> > > > clause under ctxt_has_tcrx() (and E2H set), if they are restored in the
> > > > same 'if' clause?
> > >
> > > > As you mentioned, GCS depends on TCRX, so it should be fine, but just by
> > > > reading the code I see:
> > > > - GCSCR_EL2 :
> > > > Save if GCS=1, TCRX=1, E2H=1
> > > > Restore if GCS=1, TCRX=1
> > > > - GCSPR_EL2 :
> > > > Save if GCS=1,
> > > > Restore if GCS=1, TCRX=1
> > >
> > > > Which looks kind of confusing for the as a first time reader.
> > >
> > > > Does it make sense?
> > >
> > > I agree that the current situation is a bit hard to follow, I'd actually
> > > originally written things without the explict dependency because of that
> > > but Marc wanted the optimisation.
> >
> > Well, I am not against the explicit dependency thing, it just looks odd
> > to me that some save/restore have a dependency and it's counterpart does
> > not. As well as the dependencies for both registers being different.
>
> Hey I feel the question wasn't answered completely :)
>
> Here is the reason for the asymmetric save restore (besides the tcr2
> part):
>
> GCSCR
> If guest E2H == 1:
> - L1 accesses to GCSCR_EL2 and GCSCR_EL1 have the same intent -> they
> both mean access the vCPU GCSCR_EL2.
> - L1 access to GCSCR_EL2 (e.g. msr GCSCR_EL2, x0) traps, KVM updates
> both the in-memory vCPU GCSCR_EL2, and the hardware GCSCR_EL1 for the
> the guest. In-memory copy stays up to date.
> - L1 access to GCSCR_EL1 does not trap -> in-memory vCPU GCSCR_EL2
> becomes stale if it's a write.
> - From above, must save on exit.
>
> If guest E2H == 0:
> - Only L1 accesses to GCSCR_EL2 mean access the vCPU GCSCR_EL2.
> - L1 accesses to GCSCR_EL2 always traps.
> - In-memory vCPU GCSCR_EL2 always stay up to date.
> - From above, no need to save on exit.
>
> GCSPR
> - Regardless of the guest E2H value, hardware could write to the
> hardware GCSPR_EL1, making the in-memory vCPU GCSPR_EL2 stale.
> - From above, must save on exit.
>
> Restore is trivial, vCPU GCSCR_EL2/GCSPR_EL2 must be written to the
> hardware EL1 registers because someone else could be using it.
>
> Quite a few other registers are saved only if guest E2H == 1 because of
> the same reason.
>

Ah, makes sense.
Thanks Wei-Lin!