Re: [PATCH] sched/cache: Fix use-after-free of the mm replaced by exec
From: Chen, Yu C
Date: Mon Aug 31 2026 - 00:23:27 EST
Hi Hyunwoo,
On 8/30/2026 3:30 PM, Hyunwoo Kim wrote:
When the waker cannot use the wakelist, ttwu_queue() takes the target rq
lock and goes down into update_curr(). If the target rq belongs to another
CPU, the task handed to account_mm_sched() is the one running on that CPU,
not the task being woken.
account_mm_sched() reads p->mm and updates mm->sc_stat. Nothing keeps that
mm alive. The rq lock and rq->cpu_epoch_lock it holds have nothing to do
with the lifetime of the mm.
If that task happens to be in execve(), exec_mmap() points tsk->mm and
tsk->active_mm at the new mm, and exec_mm_put_old() from setup_new_exec()
drops the old one. free_bprm() does the same when exec fails. On the way
from mmput() down to __mmdrop(), mm_destroy_sched() calls free_percpu() on
sc_stat.pcpu_sched and free_mm() returns the mm_struct.
Whoever already read the old pointer keeps using it. It adds to runtime in
the freed per-cpu area and reads sc_stat in the freed mm_struct. Depending
on the condition it also writes sc_stat.cpu. That is a use-after-free.
Commit 9f23469401b0 ("sched/cache: Fix potential NULL mm pointer access")
changed the remaining p->mm dereference to the local variable, and said the
active_mm reference keeps the structure allocated. That holds for the other
paths that detach an mm, since they take an mmgrab_lazy_tlb() reference.
exec reassigns active_mm to the new mm as well, so that reference is gone.
What is left is the mm_users reference in bprm->old_mm, and dropping it is
the free.
CPU0 CPU1
write(pipe)
try_to_wake_up()
ttwu_queue() // takes rq0 lock
enqueue_task_fair()
update_curr()
update_se()
account_mm_sched()
mm = rq0->curr->mm
// old mm
execve()
exec_mmap() // tsk->mm = new mm
setup_new_exec()
exec_mm_put_old()
mmput() -> ... -> __mmdrop()
mm_destroy_sched() // free_percpu()
free_mm()
read mm->sc_stat.epoch
// use-after-free
Ah, thanks for catching this.
---
fs/exec.c | 1 +
include/linux/sched.h | 4 ++++
kernel/events/core.c | 2 ++
kernel/sched/fair.c | 16 ++++++++++++++++
4 files changed, 23 insertions(+)
diff --git a/fs/exec.c b/fs/exec.c
index 745f6eb5279e6..6194c38807980 100644
--- a/fs/exec.c
+++ b/fs/exec.c
@@ -916,6 +916,7 @@ static void exec_mm_put_old(struct mm_struct *old_mm)
{
setmax_mm_hiwater_rss(¤t->signal->maxrss, old_mm);
mm_update_next_owner(old_mm);
+ sched_cache_exec_done();
mmput(old_mm);
}
diff --git a/include/linux/sched.h b/include/linux/sched.h
index 8b3d47a325cca..6ae31bffe049e 100644
--- a/include/linux/sched.h
+++ b/include/linux/sched.h
@@ -2415,10 +2415,14 @@ struct sched_cache_stat {
int cpu;
} ____cacheline_aligned_in_smp;
+void sched_cache_exec_done(void);
+
#else
struct sched_cache_stat { };
+static inline void sched_cache_exec_done(void) { }
+
#endif
#ifndef MODULE
diff --git a/kernel/events/core.c b/kernel/events/core.c
index a6c8e38a31104..2f29cbccf03f1 100644
--- a/kernel/events/core.c
+++ b/kernel/events/core.c
@@ -5427,6 +5427,8 @@ attach_task_ctx_data(struct task_struct *task, struct kmem_cache *ctx_cache,
if (!cd)
return -ENOMEM;
+ /* @old, loaded by the try_cmpxchg() below, is only stable under RCU. */
+ guard(rcu)();
Is this change related to this UAF issue?
+/* exec() has switched to the new mm and is about to drop the old one. */
+void sched_cache_exec_done(void)
+{
+ struct rq_flags rf;
+ struct rq *rq;
+
+ /*
+ * account_mm_sched() dereferences rq->curr->mm under this rq's lock,
+ * so a remote CPU can still be using the old mm. The lock cycle waits
+ * for it, and the store to tsk->mm cannot be reordered past the
+ * release, so later acquirers see the new mm.
+ */
+ rq = this_rq_lock_irq(&rf);
A smart fix, learnt! It behaves like a synchronize_rcu() to protect against
the read in account_mm_sched(). Small open: since the context of invoking
account_mm_sched() is preemption-disabled, I wonder if we can simply use
synchronize_rcu() directly instead of this_rq_lock_irq() - just to avoid
contention for rq-lock in heavy system?
thanks,
Chenyu