Re: [PATCH] memcg: fix integer overflow in calculate_high_delay() bypassing memory.high throttle

From: Johannes Weiner

Date: Thu Oct 29 2026 - 11:51:35 EST


On Thu, Oct 29, 2026 at 03:38:56PM +0800, zhangjiao2 wrote:
> From: zhang jiao <zhangjiao2@xxxxxxxxxxxxxxxxxxxx>
>
> calculate_high_delay() computes the throttling penalty as:
>
> penalty_jiffies = max_overage * max_overage * HZ;
>
> where max_overage is a u64 derived from the usage/high ratio shifted
> left by MEMCG_DELAY_PRECISION_SHIFT (20). When a cgroup exceeds its
> memory.high by a large factor (>= ~4096x), max_overage reaches 2^32
> and the squared multiplication overflows u64, wrapping to a small or
> zero value. A zero penalty passes the 'penalty_jiffies <= HZ / 100'
> early-exit in __mem_cgroup_handle_over_high(), so the cgroup is never
> throttled despite being massively over limit.
>
> This is exploitable for denial of service: set memory.high to a small
> value (e.g. 1 MB) and allocate several gigabytes; the overflow causes
> the throttling sleep to be skipped entirely.
>
> Additionally, on 32-bit kernels the 'unsigned long penalty_jiffies'
> intermediate truncates the u64 product before the right-shifts, which
> can also zero the result.

And then right-shifts by 34, which means the throttling was completely
inert on 32 bit. Please put this explicitly in the changelog.

> Fix both issues by:
>
> 1. Capping max_overage at (1 << 20) before squaring. Any overage
> this large already produces a penalty far above
> MEMCG_MAX_HIGH_DELAY_JIFFIES, which the caller clamps anyway, so
> the cap is lossless.
>
> 2. Using a u64 intermediate for penalty_jiffies so the right-shifts
> operate on the full 64-bit value on all architectures.
>
> The post-fix worst-case intermediate is (1<<20)^2 * HZ = 2^40 * HZ,
> which is ~2^50 for HZ=1000 and well within u64 range.
>
> Signed-off-by: zhang jiao <zhangjiao2@xxxxxxxxxxxxxxxxxxxx>
> ---
> mm/memcontrol.c | 11 ++++++++++-
> 1 file changed, 10 insertions(+), 1 deletion(-)
>
> diff --git a/mm/memcontrol.c b/mm/memcontrol.c
> index 84f4a8fd4d16..c0ab3940025c 100644
> --- a/mm/memcontrol.c
> +++ b/mm/memcontrol.c
> @@ -2576,7 +2576,7 @@ static u64 swap_find_max_overage(struct mem_cgroup *memcg)
> static unsigned long calculate_high_delay(unsigned int nr_pages,
> u64 max_overage)
> {
> - unsigned long penalty_jiffies;
> + u64 penalty_jiffies;
>
> if (!max_overage)
> return 0;
> @@ -2588,7 +2588,16 @@ static unsigned long calculate_high_delay(unsigned int nr_pages,
> * memcg in question makes it clear that it has no intention of stopping
> * its crazy behaviour, so we exponentially increase the delay based on
> * overage amount.
> + *
> + * Cap max_overage before squaring to prevent integer overflow that
> + * could otherwise wrap the penalty to zero and bypass throttling.
> + * Use a u64 intermediate so the right-shifts are not truncated on
> + * 32-bit kernels. Any overage large enough to hit the cap already
> + * produces a penalty well above MEMCG_MAX_HIGH_DELAY_JIFFIES, which
> + * the caller enforces regardless, so capping is lossless.
> */
> + max_overage = min_t(u64, max_overage, 1ULL << 20);

This is a bit of a magic value. The simpler fix is the u64 and then do
the multiplications with check_mul_overflow():

if (check_mul_overflow(max_overage, max_overage, &penalty_jiffies) ||
check_mul_overflow(penalty_jiffies, (u64)HZ, &penalty_jiffies))
return MEMCG_MAX_HIGH_DELAY_JIFFIES;

> penalty_jiffies = max_overage * max_overage * HZ;
> penalty_jiffies >>= MEMCG_DELAY_PRECISION_SHIFT;
> penalty_jiffies >>= MEMCG_DELAY_SCALING_SHIFT;

I would then also make the function return u64 and make the
penalty_jiffies in __mem_cgroup_handle_over_high() u64 as well, since
that's the place where the final clamping occurs, so this function
does not have to worry about it before the return.