Re: [PATCH net-next 14/14] netfilter: cttimeout: annotate data-races around the default timeouts
From: netdev-bot+sashiko
Date: Tue Nov 10 2026 - 01:08:40 EST
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- [Medium] A concurrent sysctl write to a default conntrack timeout can
still be silently undone.
--
netfilter: cttimeout: annotate data-races around the default timeouts
This commit changes the l4proto nlattr_to_obj() and obj_to_nlattr()
timeout callbacks to use WRITE_ONCE() and READ_ONCE() instead of plain
accesses. It targets races between cttimeout_default_set() and
cttimeout_default_get(), the conntrack packet path, and the
nf_conntrack_*_timeout* sysctl handlers, which all touch the same
per-netns default timeout arrays.
> diff --git a/net/netfilter/nf_conntrack_proto_udp.c b/net/netfilter/nf_conntrack_proto_udp.c
> index 99eedaa2b1183..777b21da3bcff 100644
> --- a/net/netfilter/nf_conntrack_proto_udp.c
> +++ b/net/netfilter/nf_conntrack_proto_udp.c
> @@ -155,16 +155,16 @@ static int udp_timeout_nlattr_to_obj(struct nlattr *tb[],
> timeouts = un->timeouts;
>
> /* set default timeouts for UDP. */
> - timeouts[UDP_CT_UNREPLIED] = un->timeouts[UDP_CT_UNREPLIED];
> - timeouts[UDP_CT_REPLIED] = un->timeouts[UDP_CT_REPLIED];
> + WRITE_ONCE(timeouts[UDP_CT_UNREPLIED], READ_ONCE(un->timeouts[UDP_CT_UNREPLIED]));
> + WRITE_ONCE(timeouts[UDP_CT_REPLIED], READ_ONCE(un->timeouts[UDP_CT_REPLIED]));
[Severity: Medium]
Can a concurrent sysctl write still be lost here?
cttimeout_default_set() passes a NULL destination:
net/netfilter/nfnetlink_cttimeout.c:cttimeout_default_set() {
...
ret = ctnl_timeout_parse_policy(NULL, l4proto, info->net,
cda[CTA_TIMEOUT_DATA]);
...
}
So udp_timeout_nlattr_to_obj() sets timeouts to un->timeouts, and the
default copy turns into a self-copy of the live per-netns array:
WRITE_ONCE(un->timeouts[UDP_CT_REPLIED],
READ_ONCE(un->timeouts[UDP_CT_REPLIED]));
That is still a separate load and store. The sysctl handler writes the
same field through proc_dointvec_jiffies() and does not take the nfnl
mutex. Take a request that carries only CTA_TIMEOUT_UDP_UNREPLIED, sent
while nf_conntrack_udp_timeout_stream is being written:
CPU0 (IPCTNL_MSG_TIMEOUT_DEFAULT_SET)
old = READ_ONCE(un->timeouts[UDP_CT_REPLIED])
CPU1 (sysctl write)
WRITE_ONCE(un->timeouts[UDP_CT_REPLIED], new)
CPU0
WRITE_ONCE(un->timeouts[UDP_CT_REPLIED], old)
The sysctl value gets reverted, even though the netlink request never
named that attribute.
The second KCSAN splat in the commit message (proc_int_u2k_conv_uop vs
udp_timeout_nlattr_to_obj) comes from this access pair. Once both sides
are marked, KCSAN stops reporting it, but the update can still be lost.
The same self-copy happens in these places:
tcp_timeout_nlattr_to_obj(), where timeouts = tn->timeouts and the
loop covers all TCP_CONNTRACK_TIMEOUT_MAX entries
sctp_timeout_nlattr_to_obj(), where timeouts = sn->timeouts
gre_timeout_nlattr_to_obj(), where timeouts = gre_get_timeouts(net)
the else branch of generic_timeout_nlattr_to_obj(), when timeout is
&gn->timeout
the else branch of icmpv6_timeout_nlattr_to_obj(), when timeout
falls back to icmpv6_get_timeouts(net)
When the destination already points at the per-netns array, could the
default copy be skipped, so that fields missing from the request are
never stored?
>
> if (tb[CTA_TIMEOUT_UDP_UNREPLIED]) {
> - timeouts[UDP_CT_UNREPLIED] =
> - ntohl(nla_get_be32(tb[CTA_TIMEOUT_UDP_UNREPLIED])) * HZ;
> + WRITE_ONCE(timeouts[UDP_CT_UNREPLIED],
> + ntohl(nla_get_be32(tb[CTA_TIMEOUT_UDP_UNREPLIED])) * HZ);
> }
[ ... ]
--
Sashiko AI review · https://netdev-ai.bots.linux.dev/sashiko/#/patchset/20261109025425.328445-1-jiayuan.chen%40linux.dev