Okay my apologizes to continue this TERRIBLY OFF TOPIC thread but
something has to be set straight here. The above is a limit - it
doesn't prove that 0/0=a. In a slightly better form, since people are
always abusing things likes limits and infiinites heres the definition.:
DEFINITION
Let f be a function defined on some open interval that contains a number
a, except possibly a itself. Then we say that the limit of f(x) as x
approaches a is L, and we write
lim f(x) = L
x->a
if for every number E > 0 there is a corresponding number d >0 such that
|f(x) - L| < E whenever 0 < |x-a| < d
>From this you should see that your "proof" fails.
D. Ryan Willhoit