> root@chaos.analogic.com wrote:
> > To make this more clear. Observe:
> >
> > switch(foo)
> > {
> > case 0:
> > case 1:
> > case 2:
> > default:
> > }
> >
> > This is basically a NOP. Perfectly legal (and useless).
>
> Try compiling that code with "gcc -pedantic" and you will find that
> this is not legal ANSI C. It is legal in gcc because it is a gcc
> extension.
>
> Try compiling with g++, and you will get a parse error.
>
> Ronnie Misra rgmisra@mit.edu
> 3 Ames Street, Box 152
> Cambridge, MA 02142
> (617) 225-6365
Yes. You are correct. I tried it with several 'non-gcc, non-unix'
compilers and they seem to require that a switch include at least
one statement within it. A ';' will suffice. I don't know if this
is really ANSI, someone else will probably comment.
FYI lint finds nothing wrong with it. Further {} seems to be okay
as well as {;}, so I can't guess what rule is being violated.
Cheers,
Dick Johnson
***** FILE SYSTEM WAS MODIFIED *****
Penguin : Linux version 2.2.6 on an i686 machine (400.59 BogoMips).
Warning : It's hard to remain at the trailing edge of technology.
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