>> #define strcpy(a,b) (char *)memcpy(a,b,strlen(b))
> As I understand, it first finds the length of b and then in second
> pass it copies the data. It would be even faster if we could do it
> with 1 pass (but fast like memcpy).
Does it do that right? I have a feeling it fails to copy the
terminating \0 byte, thus leaving an unterminated string - remember
that strlen does NOT include the \0 in the count it returns...
Best wishes from Riley.
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