Re: [RFC] mod_timer() helper functions?
From: Andrew Morton
Date: Sun May 17 2009 - 04:05:24 EST
On Sun, 17 May 2009 00:50:55 -0700 Chris Peterson <cpeterso@xxxxxxxxxxxx> wrote:
> >> Reviewing the kernel's nearly one-thousand calls to mod_timer(), there
> >> are three basic patterns:
> >>
> >> __* multi-second timeouts
> >> __* millisecond timeouts
> >> __* +1 jiffie ASAP events
> >>
>
> Is there a functional difference between the following "expire this
> timer ASAP" statements?
>
> mod_timer(timer, jiffies + 1); /* 48 uses */
> mod_timer(timer, jiffies); /* 44 uses */
> mod_timer(timer, jiffies - 1); /* 6 uses */
That's something which has always worried me. Lots of code does:
mod_timer(timer, jiffies + 1);
(for varying values of "1"). What happens if this thread of control
then gets stalled for a couple of jiffies. Say it gets preempted or
there's a long interrupt or whatever. So there's a several-jiffy
interval between the caller evaluating jiffies+1 and the entry to
mod_timer().
>From my reading, we'll hit
int i;
/* If the timeout is larger than 0xffffffff on 64-bit
* architectures then we use the maximum timeout:
*/
if (idx > 0xffffffffUL) {
idx = 0xffffffffUL;
expires = idx + base->timer_jiffies;
}
i = (expires >> (TVR_BITS + 3 * TVN_BITS)) & TVN_MASK;
vec = base->tv5.vec + i;
and the timer gets scheduled at some time in the far-distant future!
But this is such a glaring and huge problem that surely it cannot
exist. But I don't know why not.
If the bug _does_ exist then mod_timer(timer, jiffies - 1) will set the
timer to go off in the far future. mod_timer(timer, jiffies) will
usually make it go off real soon now, but it's scary. mod_timer(timer,
jiffies + 1) is safer, but still vulnerable.
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