Re: [PATCH] regulator: core: Still free GPIOs using gpio_free()

[Mark Brown]

On Tue, Jul 01, 2014 at 01:06:22PM +0100, Russell King - ARM Linux wrote:
> On Tue, Jul 01, 2014 at 12:55:26PM +0100, Mark Brown wrote:

> > Even though we mostly use GPIO descriptors internally we still use
> > gpio_request_one() to request so we need to pair that with gpio_free() to
> > release the GPIO.

> This doesn't explain the reason...  I see the current GPIO code doing this:

> void gpio_free(unsigned gpio)
> {
>         gpiod_free(gpio_to_desc(gpio));
> }
> EXPORT_SYMBOL_GPL(gpio_free);

Huh, good point (though it still seems a bit neater to match up the
request and release functions I guess).  Linus?

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