[ceph] what's going on with d_rehash() in splice_dentry()?

From: Al Viro
Date: Fri Feb 26 2016 - 12:43:00 EST


You have, modulo printks and BUG_ON(),
{
struct dentry *realdn;
/* dn must be unhashed */
if (!d_unhashed(dn))
d_drop(dn);
realdn = d_splice_alias(in, dn);
if (IS_ERR(realdn)) {
if (prehash)
*prehash = false; /* don't rehash on error */
dn = realdn; /* note realdn contains the error */
goto out;
} else if (realdn) {
dput(dn);
dn = realdn;
}
if ((!prehash || *prehash) && d_unhashed(dn))
d_rehash(dn);

When d_splice_alias() returns NULL it has hashed the dentry you'd given it;
when it returns a different dentry, that dentry is also returned hashed.
IOW, d_rehash(dn) in there should never be called.

If you have a case when it _is_ called, you've found a bug somewhere and
I'd like to see details. AFAICS, the whole prehash thing appears to be
pointless - even the place where we modify *prehash, since in that case
we return ERR_PTR() and the only caller passing non-NULL prehash (&have_lease)
buggers off on such return value past all code that would look at have_lease
value.

One possible reading is that you want to prevent hashing in !have_lease
case of
dn = splice_dentry(dn, in, &have_lease);
If that's the case, you might have a problem, since it will be hashed no
matter what...

PS: the proof that d_splice_alias() always hashes is simple - if you exclude
the places where it returns ERR_PTR(), you are left with
d_rehash(dentry);
return NULL;
in the very end,
__d_move(new, dentry, false);
...
return new;
and
int err = __d_unalias(inode, dentry, new);
...
// err turned out to be zero
return new;
The first one is obvious - we return NULL after an explicit d_rehash() of
the argument. __d_move() is guaranteed to return with its first argument
hashed due to
__d_drop(dentry);
__d_rehash(dentry, d_hash(target->d_parent, target->d_name.hash));
(dentry here refers to the first argument of __d_move() - it's our 'new').
And zero-returning __d_unalias() ends up calling __d_move(), with the
third argument of __d_unalias() ending up as the first one of __d_move().
So in both remaining cases we return a dentry that has just been hashed.