Re: [PATCH V14 13/24] mmc: block: Add blk-mq support

[Adrian Hunter]

On 27/11/17 13:23, Ulf Hansson wrote:
> On 27 November 2017 at 11:20, Adrian Hunter <adrian.hunter@xxxxxxxxx> wrote:
>> On 24/11/17 12:12, Ulf Hansson wrote:
>>> [...]
>>>
>>>> +/* Single sector read during recovery */
>>>> +static void mmc_blk_ss_read(struct mmc_queue *mq, struct request *req)
>>>
>>> Nitpick: I think mmc_blk_read_single() would be better as it is a more
>>> clear name. Would you mind changing it?
>>>
>>>> +{
>>>> +       struct mmc_queue_req *mqrq = req_to_mmc_queue_req(req);
>>>> +       blk_status_t status;
>>>> +
>>>> +       while (1) {
>>>> +               mmc_blk_rw_rq_prep(mqrq, mq->card, 1, mq);
>>>> +
>>>> +               mmc_wait_for_req(mq->card->host, &mqrq->brq.mrq);
>>>> +
>>>> +               /*
>>>> +                * Not expecting command errors, so just give up in that case.
>>>> +                * If there are retries remaining, the request will get
>>>> +                * requeued.
>>>> +                */
>>>> +               if (mqrq->brq.cmd.error)
>>>> +                       return;
>>>
>>> What happens here if the reason to the error is because the card was removed?
>>
>> Assuming the rescan is waiting for the host claim, the next read / write
>> request will end up calling mmc_detect_card_removed() in the recovery.
>> After that all following requests will error immediately because
>> mmc_mq_queue_rq() calls mmc_card_removed().
> 
> Yep, that seems reasonable. I have also tested this, so it seems to
> work as expected and similar as before.
> 
>>
>>>
>>> I guess next time __blk_err_check() is called from the
>>> mmc_blk_mq_rw_recovery(), this will be detected and managed?
>>>
>>>> +
>>>> +               if (blk_rq_bytes(req) <= 512)
>>>
>>> Shouldn't you check "if (blk_rq_bytes(req) <  512)"? How would you
>>> otherwise read the last 512 bytes block?
>>
>> At this point we have read the last sector but not updated the request, so
>> the number of bytes left should be 512.  The reason we don't update the
>> request is so that the logic in mmc_blk_mq_complete_rq() will work.  I will
>> add a comment.
> 
> Not sure I get that, but I assume the comment will help me understand. :-)
> 
>>
>>>
>>>> +                       break;
>>>> +
>>>> +               status = mqrq->brq.data.error ? BLK_STS_IOERR : BLK_STS_OK;
>>>> +
>>>> +               blk_update_request(req, status, 512);
>>>
>>> Shouldn't we actually bail out, unless the error is a data ECC error?
>>> On the other hand, I guess if it a more severe error, cmd.error will
>>> anyway be set above!?
>>>
>>> One more question, if there is a data error, we may want to try to
>>> recover by sending a stop command? How do we manage that?
>>
>> I was thinking a single-block read would not need a stop.  I will think
>> some more about error handling here.
> 
> Great!
> 
> Anyway, you may be right -  and perhaps it may not be worth adding
> error handling, especially if it complicates the code a lot.
> 
> [...]
> 
>>>> +static void mmc_blk_mq_acct_req_done(struct mmc_queue *mq, struct request *req)
>>>
>>> Nitpick: Can we please try to find a better name for this function. I
>>> don't think "acct" is good abbreviation because, to me, it's not
>>> self-explaining.
>>
>> What about mmc_blk_mq_decrement_in_flight() ?
> 
> Looks good, or perhaps even: mmc_blk_mq_dec_in_flight().
> 
>>
>>>
>>>> +{
>>>> +       struct request_queue *q = req->q;
>>>> +       unsigned long flags;
>>>> +       bool put_card;
>>>> +
>>>> +       spin_lock_irqsave(q->queue_lock, flags);
>>>> +
>>>> +       mq->in_flight[mmc_issue_type(mq, req)] -= 1;
>>>> +
>>>> +       put_card = (mmc_tot_in_flight(mq) == 0);
>>>> +
>>>> +       spin_unlock_irqrestore(q->queue_lock, flags);
>>>> +
>>>> +       if (put_card)
>>>> +               mmc_put_card(mq->card, &mq->ctx);
>>>
>>> I have tried to convince myself that the protection of calling
>>> mmc_get|put_card() is safe, but I am not sure.
>>>
>>> I am wondering whether there could be races for mmc_get|put_card().
>>> Please see some more related comments below.
>>
>> mmc_put_card() is safe and necessary if we have seen mmc_tot_in_flight(mq)
>> == 0.  When the next request arrives it will have to do a mmc_get_card()
>> because it is changing the number of requests in flight from 0 to 1.  It
>> doesn't matter if that mmc_get_card() comes before or after or during this
>> mmc_put_card().
>>
>>>
>>> [...]
> 
> [...]
> 
>>>
>>> Anyway, then if using a queue_depth of 64, how will you make sure that
>>> you not end up having > 1 requests being prepared at the same time
>>> (not counting the one that may be in transfer)?
>>
>> We are currently single-threaded since every request goes through
>> hctx->run_work when BLK_MQ_F_BLOCKING and nr_hw_queues == 1.  It might be
>> worth adding a mutex to ensure that never changes.
>>
>> This point also answers some of the questions below, since there can be no
>> parallel dispatches.
> 
> Yeah, it clearly does. Thanks!
> 
>>>> +
>>>> +enum mmc_issued mmc_blk_mq_issue_rq(struct mmc_queue *mq, struct request *req)
>>>> +{
>>>> +       struct mmc_blk_data *md = mq->blkdata;
>>>> +       struct mmc_card *card = md->queue.card;
>>>> +       struct mmc_host *host = card->host;
>>>> +       int ret;
>>>> +
>>>> +       ret = mmc_blk_part_switch(card, md->part_type);
>>>
>>> What if there is an ongoing request, shouldn't you wait for that to
>>> complete before switching partition?
>>
>> Two requests on the same queue cannot be on different partitions because we
>> have a different queue (and block device) for each partition.
> 
> That's not true for RPMB anymore I am afraid.
> 
> RPMB shares the same queue as for the main eMMC partition, which is
> because we strive towards fair I/O scheduling across the hole device.

I hadn't thought of RPMB, but I think the logic is OK, which is good because
it is the same as we presently have.  Here the md->part_type will be the
main area even for RPMB.  So this switch won't do anything if we have a
request in flight.  Then inside __mmc_blk_ioctl_cmd() the switch to RPMB is
done, and afterwards mmc_blk_issue_drv_op() switches it back again.

> 
>>
>>>
>>>> +       if (ret)
>>>> +               return MMC_REQ_FAILED_TO_START;
>>>> +
>>>> +       switch (mmc_issue_type(mq, req)) {
>>>> +       case MMC_ISSUE_SYNC:
>>>> +               ret = mmc_blk_wait_for_idle(mq, host);
>>>> +               if (ret)
>>>> +                       return MMC_REQ_BUSY;
>>>
>>> Wouldn't it be possible that yet a new SYNC request becomes queued in
>>> parallel with this current one. Then, when reaching this point, how do
>>> you make sure that new request waits for the current "SYNC" request?
>>
>> As mentioned above, there are no parallel dispatches.
>>
>>>
>>> I mean is the above mmc_blk_wait_for_idle(), really sufficient to deal
>>> with synchronization?
>>
>> So long as there are no parallel dispatches.
>>
>>>
>>> I guess we could use mmc_claim_host(no-ctx) in some clever way to deal
>>> with this, or perhaps there is a better option?
>>
>> We are relying on there being no parallel dispatches.  That is the case now,
>> but if it weren't we could use a mutex in mmc_mq_queue_rq().
>>
> 
> Yeah, but then leave that until needed.
> 
>>>
>>> BTW, I guess the problem is also present if there is SYNC request
>>> ongoing and then is a new ASYNC request coming in. Is the ASYNC
>>> request really waiting for the SYNC request to finish?
>>
>> With no parallel dispatches, the SYNC request runs to completion before
>> another request can be dispatched.
> 
> Yes, I get it now. Thanks for clarifying this!
> 
> [...]
> 
>>>> +static blk_status_t mmc_mq_queue_rq(struct blk_mq_hw_ctx *hctx,
>>>> +                                   const struct blk_mq_queue_data *bd)
>>>> +{
>>>> +       struct request *req = bd->rq;
>>>> +       struct request_queue *q = req->q;
>>>> +       struct mmc_queue *mq = q->queuedata;
>>>> +       struct mmc_card *card = mq->card;
>>>> +       enum mmc_issue_type issue_type;
>>>> +       enum mmc_issued issued;
>>>> +       bool get_card;
>>>> +       int ret;
>>>> +
>>>> +       if (mmc_card_removed(mq->card)) {
>>>> +               req->rq_flags |= RQF_QUIET;
>>>> +               return BLK_STS_IOERR;
>>>> +       }
>>>> +
>>>> +       issue_type = mmc_issue_type(mq, req);
>>>> +
>>>> +       spin_lock_irq(q->queue_lock);
>>>> +
>>>> +       switch (issue_type) {
>>>> +       case MMC_ISSUE_ASYNC:
>>>> +               break;
>>>> +       default:
>>>> +               /*
>>>> +                * Timeouts are handled by mmc core, and we don't have a host
>>>> +                * API to abort requests, so we can't handle the timeout anyway.
>>>> +                * However, when the timeout happens, blk_mq_complete_request()
>>>> +                * no longer works (to stop the request disappearing under us).
>>>> +                * To avoid racing with that, set a large timeout.
>>>> +                */
>>>> +               req->timeout = 600 * HZ;
>>>> +               break;
>>>> +       }
>>>> +
>>>> +       mq->in_flight[issue_type] += 1;
>>>> +       get_card = (mmc_tot_in_flight(mq) == 1);
>>>> +
>>>> +       spin_unlock_irq(q->queue_lock);
>>>> +
>>>> +       if (!(req->rq_flags & RQF_DONTPREP)) {
>>>> +               req_to_mmc_queue_req(req)->retries = 0;
>>>> +               req->rq_flags |= RQF_DONTPREP;
>>>> +       }
>>>> +
>>>> +       if (get_card)
>>>
>>> Coming back to the get_card() thingy, which I wonder if it's fragile.
>>>
>>> A request that finds get_card == true here, doesn't necessarily have
>>> to reach to this point first (the task may be preempted), in case
>>> there is another request being queued in parallel (or that can't
>>> happen?).
>>>
>>> That could then lead to that the following steps become executed for
>>> the other requests, prior anybody calling mmc_get_card().
>>
>> You are right, this logic does not support parallel dispatches.
>>
> 
> This do raises a question, don't you think it would be beneficial,
> especially for CQE to allow parallel dispatches?
> 
> I am not saying we should change this at this point, just that we may
> consider changing this for future improvements.

I think the benefit is limited because the time to dispatch a request is
small compared with the time to complete a request. i.e. a number of
requests can be queued before the first one has completed.  But yes, it is
something to keep in mind.