Yes, when arch customization and __builtint_prefetch are implemented with
On 29.05.24 г. 6:20 ч., Youling Tang wrote:
From: Youling Tang <tangyouling@xxxxxxxxxx>
After commit ab483570a13b ("x86 & generic: change to __builtin_prefetch()"),
x86_64 directly uses __builtin_prefetch() without the specific implementation
of prefetch(). Also, x86_64 use a generic definition until commit ae2e15eb3b6c
("x86: unify prefetch operations"). So remove it.
So this patch just ensures the x86-specific prefetch() implementation is defined only for 32bit case, otherwise we have it defined for the 64bit case as well but effectively it's not used since ARCH_HAS_PREFETCH is not defined for 64bit, meaning in the 64bit case prefetch() is still defined to __builtint_prefetch in include/linux/prefetch.h.
In essence this is a purely cosmetic cleanup , am I right?
I compiled a file that utilizes prefetch with and without your patch and the generated assembly is identical.
Reviewed-by: Nikolay Borisov <nik.borisov@xxxxxxxx>
Signed-off-by: Youling Tang <tangyouling@xxxxxxxxxx>
---
arch/x86/include/asm/processor.h | 7 ++++---
1 file changed, 4 insertions(+), 3 deletions(-)
diff --git a/arch/x86/include/asm/processor.h b/arch/x86/include/asm/processor.h
index cb4f6c513c48..44371bdcc59d 100644
--- a/arch/x86/include/asm/processor.h
+++ b/arch/x86/include/asm/processor.h
@@ -599,9 +599,6 @@ extern char ignore_fpu_irq;
#ifdef CONFIG_X86_32
# define BASE_PREFETCH ""
# define ARCH_HAS_PREFETCH
-#else
-# define BASE_PREFETCH "prefetcht0 %1"
-#endif
/*
* Prefetch instructions for Pentium III (+) and AMD Athlon (+)
@@ -616,6 +613,10 @@ static inline void prefetch(const void *x)
"m" (*(const char *)x));
}
+#else
+# define BASE_PREFETCH "prefetcht0 %1"
+#endif
+
/*
* 3dnow prefetch to get an exclusive cache line.
* Useful for spinlocks to avoid one state transition in the