But it doesn't work this way. It looks like this:
fd1 = open ("/usr");
fd2 = open ("/usr/src");
fd3 = open ("/usr/X11");
poll (fd1...fd3);
So there's no denial of service. You may as well argue that open() is
a potential denial of service.
> ... here kernel needs to remember what I polled and when, because I c
> an do
>
> poll("/usr")
>
> again. This seems to me like pretty trivial attach.
Nope. Read the code.
Regards,
Richard....
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